The correct answer should be D) 5/6
hope this helps :)
Answer:
f ( x ) does not satisfy the mean value theorem
Step-by-step explanation:
The given data :-
- f(x) = 3x - 4 cos ( 2x + 1 )
- f'(x) = 3 +8 sin ( 2x + 1 )
- The interval [ -1 , 2 ]
Solution :-
i) f(x) is continuous on [ -1 , 2 ]
ii) f(x) is derivable on ( -1 , 2 )
f ( -1 ) = 3 * (-1 ) - 4 cos [ 2 * ( -1 ) + 1 ] = - 3 + cos (-1 ) = - 3 - 4 * 0.9998 = - 6.992
f ( 2 ) = 3 * 2 - 4 cos ( 4 * 2 + 1 ) = 6 + 4 cos 9 = 6 - 3.9507 = - 3.04924
iii) f ( -1 ) ≠ f ( 2 )
f ( x ) is not real valued function so it does not satisfy the mean value theorem
Answer:
see explanation
Step-by-step explanation:
If ∠ D ≡ ∠ CED then CD ≡ CE
The base angles theorem states that if the sides of a triangle are congruent, that is isosceles triangle the the angles opposite these sides, the base angles, are equal.
Here we are using the converse of base angle theorem (b)
That is if 2 angles are congruent ( base angles ) then the sides opposite these angles are congruent.
answer
f(-5)=115
Step-by-step explanation:
x+5=0
x=-5
f(x)=3x^2-7x+5
f(-5)=3*(-5)^2-7(-5)+5
f(-5)=3*25+35+5
f(-5)=115
