Let denote a normal random variable with mean and standard deviation . (That is: .) By definition, the -score of an observation with value would be:
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In this question, the value of is given. Also given are the value of the observation and the corresponding -score, . Rearrange the -score definition to find an expression for :
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Substitute in the value of , , and to find the value of , the mean of this normal random variable:
We can work backwards using the z-score formula to find the mean. The problem gives us the values for z, x and σ. So, let's substitute these numbers back into the formula:
z−4−16−2626=x−μσ=10−μ4=10−μ=−μ=μ
We can think of this conceptually as well. We know that the z-score is −4, which tells us that x=10 is four standard deviations to the left of the mean, and each standard deviation is 4. So four standard deviations is (−4)(4)=−16 points. So, now we know that 10 is 16 units to the left of the mean. (In other words, the mean is 16 units to the right of x=10.) So the mean is 10+16=26.