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Schach [20]
3 years ago
7

Can someone help me please

Mathematics
1 answer:
kifflom [539]2 years ago
4 0

9514 1404 393

Answer:

  {Segments, Geometric mean}

  {PS and QS, RS}

  {PS and PQ, PR}

  {PQ and QS, QR}

Step-by-step explanation:

The three geometric mean relationships are derived from the similarity of the triangles the similarity proportions can be written 3 ways, each giving rise to one of the geometric mean relations.

  short leg : long leg = SP/RS = RS/SQ   ⇒   RS² = SP·SQ

  short leg : hypotenuse = RP/PQ = PS/RP   ⇒   RP² = PS·PQ

  long leg : hypotenuse = RQ/QP = QS/RQ   ⇒   RQ² = QS·QP

I find it easier to remember when I think of it as <em>the segment from R is equal to the geometric mean of the two segments the other end is connected to</em>.

__

  segments PS and QS, gm RS

  segments PS and PQ, gm PR

  segments PQ and QS, gm QR

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16. Suppose Eva has 12 3/4 pounds of flour. The day's baking will require triple that amount.
egoroff_w [7]

Answer:

Option D

Step-by-step explanation:

Given the following question:

12 \frac{3}{4} \times3

In order to find the answer, we have to convert the mixed number and then multiply by three, since how Eva needs triple the amount for today's baking.

12 \frac{3}{4} \times3
12\frac{3}{4} =4\times12=48+3=51=\frac{51}{4}
3=\frac{3}{1}
\frac{51}{4} \times\frac{3}{1}
51\times3=153
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<u>Convert the improper fraction back into a mixed number:</u>

\frac{153}{4}
\frac{153}{4} =153\div4=38\frac{1}{4}
=38\frac{1}{4}

Which means Eva needs "38 1/4 pounds of flour" or option D for today's baking.

3 0
2 years ago
y : (<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B18%5C%5C%7D" id="TexFormula1" title="\frac{3}{18\\}" alt="\frac{3}{18\\}
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Answer:

whats the given?? what you need I don't understand

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Answer:

hmmmmmmmmm

Step-by-step explanation:

$12?

i think

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3 years ago
A board of length 7 divided by the quantity x minus 2 end of quantity meters was cut into two pieces. If one piece is 3 divided
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Answer:

Length of other board =\frac{4x+20}{x^{2} -4} metres

Step-by-step explanation:

Given: Length of board = \frac{7}{x-2} metres

Length of board was divided into two.

Length of one piece = \frac{3}{x+2} metres

Let l = length of the other board

Length of the other board = Length of board - Length of one piece

So, l=\frac{7}{x-2}-\frac{3}{x+2}

l=\frac{7(x+2)-3(x-2)}{(x-2)(x+2)} \\\\l=\frac{7x+14-3x+6}{x^{2} -4} \\\\l=\frac{4x+20}{x^{2} -4}

Thus, length of the other board =\frac{4x+20}{x^{2} -4} metres

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3 years ago
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