Can someone help me please

Mathematics

1 answer:

kifflom [539]2 years ago

4 0

9514 1404 393

Answer:

{Segments, Geometric mean}

{PS and QS, RS}

{PS and PQ, PR}

{PQ and QS, QR}

Step-by-step explanation:

The three geometric mean relationships are derived from the similarity of the triangles the similarity proportions can be written 3 ways, each giving rise to one of the geometric mean relations.

short leg : long leg = SP/RS = RS/SQ ⇒ RS² = SP·SQ

short leg : hypotenuse = RP/PQ = PS/RP ⇒ RP² = PS·PQ

long leg : hypotenuse = RQ/QP = QS/RQ ⇒ RQ² = QS·QP

I find it easier to remember when I think of it as the segment from R is equal to the geometric mean of the two segments the other end is connected to.

segments PS and QS, gm RS

segments PS and PQ, gm PR

segments PQ and QS, gm QR

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For a certain horse race comma the odds in favor of a certain horse finishing in second placehorse race, the odds in favor of a

NikAS [45]

Answer:

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Step-by-step explanation:

Let A denote an event. The odds of the horse finishing second is 33 to 67.

From the information, the total outcomes of event A is:

$Total \ Outcomes, A=Favorable +Unfavorable\\\\=33+67\\\\=100$

Hence, there are 100 total outcomes. The probability of the horse finishing second is calculated as:

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Hence, the probability of finishing second is 0.33

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