Can someone help me please

Mathematics

1 answer:

kifflom [539]3 years ago

4 0

9514 1404 393

Answer:

{Segments, Geometric mean}

{PS and QS, RS}

{PS and PQ, PR}

{PQ and QS, QR}

Step-by-step explanation:

The three geometric mean relationships are derived from the similarity of the triangles the similarity proportions can be written 3 ways, each giving rise to one of the geometric mean relations.

short leg : long leg = SP/RS = RS/SQ ⇒ RS² = SP·SQ

short leg : hypotenuse = RP/PQ = PS/RP ⇒ RP² = PS·PQ

long leg : hypotenuse = RQ/QP = QS/RQ ⇒ RQ² = QS·QP

I find it easier to remember when I think of it as <em>the segment from R is equal to the geometric mean of the two segments the other end is connected to</em>.

segments PS and QS, gm RS

segments PS and PQ, gm PR

segments PQ and QS, gm QR

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The independent-samples t testResearch Scenario: A forensic psychologist has developed a new program that teaches empathy and po

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Step-by-step explanation:

Hello!

The researcher developed a treatment to teach social skills to youth offenders. To test if the treatment is effective in increasing empathy compared to the standard treatment she randomly selected a group of 9 offenders and applied the new treatment and to another group of 9 randomly selected youth offenders, she applied the standard treatment. (Note: the data corresponds to two samples of 9 units each, so I've used those sizes to conduct the test)

At the end of the treatment, she administers BES to measure their empathy levels. Her claim is that the offenders that received the new treatment will have higher BES scores than those who received the standard treatment.

1) Using the records obtained for both groups, she intends to conduct an independent t-test to analyze her claim.

X₁: BES results of a youth offender treated with the new treatment.

X₂: BES results of a youth offender treated with the standard treatment.

H₀: μ₁ = μ₂

H₁: μ₁ ≠ μ₂

α:0.05

test statistic

$t_{H_0}= -0.32$

p-value: 0.7517

The p-value is greater than the significance level so the decision is to not reject the null hypothesis. This means that at a 5% significance level you can conclude that there is no difference between the mean BES scores of the youth offenders treated with the new treatment and the mean BES score of the youth offenders treated with the standard treatment. The new treatment doesn't increase the levels of social empathy of the youth offenders.

I hope this helps

(Box plot in attachment)