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irina [24]
2 years ago
11

Simplify this expression. (100 + 4z)20

Mathematics
2 answers:
malfutka [58]2 years ago
8 0
2,080 this is what I got
Serga [27]2 years ago
7 0
The answer is 2000+80z
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Can someone help me please
masya89 [10]

Answer:

A) (3,-8); Reflection

Step-by-step explanation:

The question kind of gave you a hint. Look at how the coordinate point is arranged...

(-y,-x)

That means all positive become negatives and all negatives become positives. This gives you the coordinate of (3,-8).  

As for reflection or rotation, the image's coordinates FLIPPED, like how images do in a mirror's reflection.

This means the answer would be A) (3,-8); Reflection.

4 0
3 years ago
Given x-intercepts of -3 and 2 find and equation for a graph that goes through both points. (You do NOT have to graph the equati
lesya [120]

Answer:

1? lllllllllllll the answer is 1 I think

6 0
3 years ago
(15 pts) 4. Find the solution of the following initial value problem: y"-10y'+25y = 0 with y(0) = 3 and y'(0) = 13
jolli1 [7]

Answer:

y(x)=3e^{5x}-2xe^{5x}

Step-by-step explanation:

The given differential equation is y''-10y'+25y=0

The characteristics equation is given by

r^2-10r+25=0

Finding the values of r

r^2-5r-5r+25=0\\\\r(r-5)-5(r-5)=0\\\\(r-5)(r-5)=0\\\\r_{1,2}=5

We got a repeated roots. Hence, the solution of the differential equation is given by

y(x)=c_1e^{5x}+c_2xe^{5x}...(i)

On differentiating, we get

y'(x)=5c_1e^{5x}+5c_2xe^{5x}+c_2e^{5x}...(ii)

Apply the initial condition y (0)= 3 in equation (i)

3=c_1e^{0}+0\\\\c_1=3

Now, apply the initial condition y' (0)= 13 in equation (ii)

13=5(3)e^{0}+0+c_2e^{0}\\\\13=15+c_2\\\\c_2=-2

Therefore, the solution of the differential equation is

y(x)=3e^{5x}-2xe^{5x}

5 0
3 years ago
I need help. Please ​
GREYUIT [131]

Answer:

A=5 units squared

Step-by-step explanation:

A=1/2(l*w)

A=1/2(5*2)

A=1/2(10)

A=5

3 0
2 years ago
0.5m + 6.4 = 4.9 - 0.1m
BigorU [14]
Solve for m by simplifying both sides of the equation, then isolating the variable.
m = -2.5
5 0
3 years ago
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