No, there is significant difference in the use of e readers by different age groups.
Given sample 1 ( 29 years old)
=628,
=7%, sample 2( 30 years old)
=2309,
=0.11.
We have to first form hypothesis one null hypothesis and other alternate hypothesis.
π1-π2=0
π1-π2≠0
α=0.05
Difference between proportions 

The pooled proportion needed to calculate standard error is:

=(44+254)/(628+2309)
=0.10146
The estimated standard error of difference between means is computed using the formula:

=
=
=
=0.01315
Z= Pd-(π1-π2)/
=-0.04-0/0.013
=-3.0769
This test is a two tailed test so the p value for this test is calculated as (using z table)
p value:2 P(Z<-3.0769)
=2*0.002092
=0.004189
P value< significance level of 5%.
Hence there is enough evidence to show the claim that there is a significant difference in the use of e readers by different age groups.
Learn more about hypothesis at brainly.com/question/11555274
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Question is incomplete as it also includes:
Significance level of 5%.
Answer:
A. a one-tailed paired t-test.
Step-by-step explanation:
49.617 ( alternative form )
There’s a pattern to this and I’ll explain in the comments if you want to know or can’t figure it out :)
1.) 27/x^3
2.) a^8/b^12
3.) 7^36/81 OR 13,841,287,201/81
4.) 256m^20/n^4
5.) x^6y^6
6.) 64k^4/k^6
7.) 1,000a^9b^6/a^6b^9
8.) 81x^21/625
9.) 2304/x^16y^12
10.) x^7z^14/y^21
11.) 7,776k^5
12.) x^24y^24/4,096
Hope it’s all helped