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mote1985 [20]
3 years ago
10

What is the missing constant term in the perfect square that starts with x2 – 16x?

Mathematics
1 answer:
andre [41]3 years ago
4 0

Answer:

64

Step-by-step explanation:

the expression is

x² - 16x + _

the constant term is the square of the number residing with x divided by 2

the number number x = 16

therefore the constant term is (16/ 2)²

= 8²

= 64

the formula being used here is

(x + a)² = x² + 2ax + a²

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