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Allushta [10]
2 years ago
7

Complete the table. Will choose brainliest.

Mathematics
2 answers:
Gala2k [10]2 years ago
4 0

Answer:

        resistance      no resistance

Start:      64%                    36%

end:       33%                     67%

Step-by-step explanation:

Blizzard [7]2 years ago
3 0

Answer:

Start: 384, 216, 64 percent, 36 percent

End: 33, 67, 33 percent, 67 percent

Step-by-step explanation:

Hope I helped!

You might be interested in
A dealer bought an item for $20 sold it for 24 bought it for 25
yuradex [85]

Answer:

$3

Step-by-step explanation:

Started with $20 Sold for $24 Bought it for $25 Then sold it for $28

so, $24 -$20= so she made $4.

then she bought it for $25-$24= so she only made $1

Finally she sold it for $28-$25 so she made a total of $3

6 0
3 years ago
Can someone please help!​
kozerog [31]

Answer:

fraction 4/12 or 1/3

decimal .333333333

percent 33%.333333

Step-by-step explanation:

6 0
3 years ago
Write an equation in slope-intercept form of the line shown. (-4,0) and (1,-5)
Irina18 [472]

The slope intercept form is y = -x - 4

To find the slope intercept form given a couple of points, start by finding the slope using the slope equation.

m(slope) = (y2 - y1)/(x2 - x1)

m = (-5 - 0)/(1 - -4)

m = -5/5

m = -1

Now we look for the intercept using slope intercept form, our slope and a point.

y = mx + b

0 = -4(-1) + b

0 = 4 + b

-4 = b

Now we can use those two things top model the equation.

y = -x - 4

5 0
3 years ago
If 3x - 6 = 21, what is the value of x - 2 ?
lora16 [44]
3x-6=21
Or,3x=27
Or,x=27/3
Or,x=9
So,Now,
X-2=9-2
=7
Hope it helps
5 0
3 years ago
What is the limit of f (×) as x approaches - infinty
tatyana61 [14]
If the degree of numerator and denominator are equal, then limit will be leading coefficient of numerator divided by the leading coefficient of denominator.

So then the limit would be 3/1 = 3.

Alternatively,

\displaystyle \lim_{x\to\infty}\dfrac{3x^2+6}{x^2-4}=\displaystyle \lim_{x\to\infty}\dfrac{3x^2+6}{x^2-4}\cdot\dfrac{1/x^2}{1/x^2}=\lim_{x\to\infty}\dfrac{3+\frac6{x^2}}{1-\frac4{x^2}} = \dfrac{3+0}{1-0}=\boxed{3}

Hope this helps.
5 0
3 years ago
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