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rewona [7]
3 years ago
8

A box contains 17 ​transistors, 3 of which are defective. If 3 are selected at​ random, find the probability that

Mathematics
2 answers:
Margarita [4]3 years ago
6 0
B none are defective

My name is Ann [436]3 years ago
3 0
Use Binomial Theorem
P(x=k) = (nCk) p^k (1-p)^{n-k}
Where k is number that are defective, n is total selected (3), and p is probability that a transistor is defective (3/17).

a) All are defective means k = 3
P = (3C3) (\frac{3}{17})^3 (\frac{14}{17})^0 = (\frac{3}{17})^3 = 0.0055

b) None are defective means k = 0
P = (3C0) (\frac{3}{17})^0 (\frac{14}{17})^3 = (\frac{14}{17})^3 = 0.5585
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