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alex41 [277]
2 years ago
6

Pls can anybody give me the code to join khan academy online classes​

Mathematics
1 answer:
Dahasolnce [82]2 years ago
4 0

Answer:

your teacher has to give it to you :)

students cant

Step-by-step explanation:

You might be interested in
Blank -10= -7<br><br> Missing value
mario62 [17]

Answer:

3

Step-by-step explanation:

a positive 3 taken away from a negative 10 leaves you with less negative but still in the negative which means you get -7 so 3 is the blank

8 0
2 years ago
Determine the number of outcomes in the event. Decide whether the event is a simple event or not. You randomly select one card f
Marat540 [252]

Answer:

No we can consider A as single event. See the explanation below

Step-by-step explanation:

Let's define the event A as:

A=" Select a 4 from a standard deck of 52 cards"

We know that in a standard deck we have 4 different types of 4, spade, heart, diamond and club.

And by definition of simple event we need to have just one possible outcome in the experiment, and on this case we have 4 possible options for event A, so for this reason the event A can't be considered as simpl event.

3 0
3 years ago
If f(x)=x-6 and g(x)=x^1/2(x+3) what is f(x) times g(x
dimaraw [331]
This  is (x - 6)*x^1/2(x + 3)

= x^1/2 (x^2 - 3x - 18)

= x^(5/2) - 3x^(3/2) - 18x^(1/2)
7 0
3 years ago
Read 2 more answers
Prove that one of every three consecutive positive integer is divisible by 3
Inessa05 [86]
Hello : 
all n in N ; n(n+1)(n+2) = 3a    a in  N  or : <span>≡ 0 (mod 3)
1 ) n </span><span>≡ 0 ( mod 3)...(1)

     n+1 </span>≡ 1 ( mod 3)...(2)
      n+2 ≡ 2 ( mod 3)...(3)
by (1), (2), (3)  : n(n+1)(n+2) ≡ 0×1×2   ( mod 3)   : ≡ 0 (mod 3)
2) n ≡ 1 ( mod 3)...(1)

     n+1 ≡ 2 ( mod 3)...(2)
      n+2 ≡ 3 ( mod 3)...(3)
by (1), (2), (3)  : n(n+1)(n+2) ≡ 1×2 × 3  ( mod 3)   : ≡ 0 (mod 3) , 6≡ 0 (mod)
 3) n  ≡ 2 ( mod 3)...(1)

     n+1 ≡ 3 ( mod 3)...(2)
      n+2 ≡ 4 ( mod 3)...(3)
by (1), (2), (3)  : n(n+1)(n+2) ≡ 2×3 × 4  ( mod 3)   : ≡ 0 (mod 3) , 24≡ 0      (mod3)
5 0
3 years ago
Let f(x)= 100 / −10+ e^ −0.1x . What is f(−6) ?
bija089 [108]

The value of f(-6) is -12.2

Explanation:

Given that the function f(x)=\frac{100}{-10+e^{-0.1\left(x\right)}}

We need to determine the value of f(-6)

The value of f(-6) can be determined by substituting the value for x=-6 in the function and simplify the function.

Hence, let us substitute x=-6 in the function, we get,

f(-6)=\frac{100}{-10+e^{-0.1\left(-6\right)}}

Let us apply the rule -\left(-a\right)=a , we get,

f(-6)=\frac{100}{-10+e^{0.1\left(6\right)}}

Multiplying the numbers, we get,

f(-6)=\frac{100}{-10+e^{0.6}}

The value of e^{0.6}=1.822

Substituting the value of e^{0.6}=1.822 , we get,

f(-6)=\frac{100}{-10+1.822}

Subtracting the denominator, we have,

f(-6)=\frac{100}{-8.178}

Dividing, we have,

f(-6)=-12.228

Rounding off to the nearest tenth, we have,

f(-6)=-12.2

Thus, the value of f(-6) is -12.2

4 0
3 years ago
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