By simplifying . This will result in a simplified version of .
The Simplifying Algorithm is a wonderful way to simplify complex mathematics problems. It can be used to solve equations, convert fractions to decimals, and perform many other math operations. In this problem, the Simplifying Algorithm will help you reduce
Since two opposites add up to 0, remove them from the expression.
Write all numerators above the least common denominator 5x2
Use the commutative property to reorder the terms so that constants on the left
Rearrange the terms
By reording the terms
Hence, by simplifying this equation, divide both numerator and denominator. This will result in a simplified version of .
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Answer:
There were 7 cats
Step-by-step explanation:
In this question, we are asked to calculate the number of individual cats and dogs present at an animal shelter on a certain Monday.
Since we do not know the exact numbers, let’s represent these animals by variables. Let the number of dogs be d and the number of cats be c .
Since there are a total of 9 animals, this means;
c + d = 9 •••••••••(I)
Let’s now get the second equation out of their finances;
Total amount spent on dogs will be 7 * d = 7d while total amount spent on cats will be 5.5 * c = 5.5c. If we add both, we will get the total amount spent which is $52.5
Mathematically therefore;
5.5c + 7d = 52.5 ••••••••(ii)
Now from 1, we can say that c = 9 - d
Let’s substitute this in ii
5.5(9-d) + 7d = 52.5
49.5 - 5.5d + 7d = 52.5
1.5d = 52.5 - 49.5
1.5d = 3
d = 3/1.5 = 2
Since d = 2, c = 9 - d = 9 - 2 = 7
Answer:
The Hotel charge without tax in first city is $3500 and The hotel charge before tax in the second city is 2000
Step-by-step explanation:
Let x be the hotel charge without tax in first city
We are given that The hotel charge before tax in the second city was $1500 lower than in the first.
So, Hotel charge without tax in second city =x-1500
Tax% in first city = 10%
So, tax in first city = 0.1x
Tax% in second city =5%
So, tax in second city = 0.05(x-1500)
We are given that The total hotel tax paid for the two cities was $600.
So,0.1x+0.05(x-1500)=600
0.1x+0.05x+75=600
0.15x=600-75
x=3500
Hotel charge without tax in first city = $3500
The hotel charge before tax in the second city =x-1500=3500-1500=2000
Hence The Hotel charge without tax in first city is $3500 and The hotel charge before tax in the second city is 2000
I hope this helps you
-(2.4+1/2)÷(-)(2.3+2/3)
-9/2÷ -8/3
9/2×3/8
27/24
1 3/24