A quadrilateral with only one pair of opposite sides parallel and the other pair of opposite sides congruent is a(n)

Application

user100 [1]

He needs to run with approximately 6429 for a distance of 9 km

<h3>How to determine the number of strides?</h3>

The given parameters are:

Length of stride = 1.4 m

Distance for marathon = 9 km

The number of strides needed is then calculated as:

Number of stride = Distance for marathon/Length of stride

Substitute the known values in the above equation

Number of stride = 9km/1.4m

Convert km to m

Number of stride = 9000m/1.4m

Evaluate the quotient

Number of stride = 6428.57143

Approximate the estimate

Number of stride = 6429

Hence, he needs to run with approximately 6429 for a distance of 9 km

Read more about quotients at:

brainly.com/question/8952483

#SPJ1

6 0

2 years ago

Someone please help me with this! <br>|-2-8x|-5<61

Mrac [35]

For
|a|<b
assume
-b<a<b
so

add 5 to both side
|-2-8x|<66
assume

-66<-2-8x<66
add 2 to both sides
-64<-8x<68
divide everyboy by -8, don't forget to flip sign
8>x>-8.5
-8.5<x<8

the solution is all numbers between -8.5 and 8, not including -8.5 and 8
in interval notation: (-8.5,8)
or
S={x|-8.5<x<8}

3 0

3 years ago

In a multiple choice quiz there are 5 questions and 4 choices for each question (a, b, c, d). Robin has not studied for the quiz

Ahat [919]

Answer:

a) There is a 18.75% probability that the first question that she gets right is the second question.

b) There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

c) There is a 10.35% probability that she gets the majority of the questions right.

Step-by-step explanation:

Each question can have two outcomes. Either it is right, or it is wrong. So, for b) and c), we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem we have that:

Each question has 4 choices. So for each question, Robin has a $\frac{1}{4} = 0.25$ probability of getting ir right. So $\pi = 0.25$ . There are five questions, so $n = 5$ .

(a) What is the probability that the first question she gets right is the second question?

There is a 75% probability of getting the first question wrong and there is a 25% probability of getting the second question right. These probabilities are independent.

So

$P = 0.75(0.25) = 0.1875$