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3 years ago

True or False: A rectangular equation that is not a function may be a function in the polar coordinate system

Mathematics

2 answers:

Goryan [66]3 years ago

6 0

I think it should be true but if im wrong sorry its my best educated guess

olga_2 [115]3 years ago

5 0

The statement is true.

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$5,000 is invested in two different accounts yielding 3% and 3.5% interest. The interest earned on the two accounts is $155.

Kryger [21]

0.03x+0.035 (5000-x)=155
Solve for x
X=4000 invested at 3%
5000-4000=1000 invested at 3.5%

6 0

3 years ago

Hey can any one tell me if 5/√5 is rational or irrational

irina1246 [14]

Answer:

Irrational

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

164.38 in expanded form

tekilochka [14]

It is this 100 60 40 30 800

6 0

3 years ago

George is considering two different investment options. The first offers 7.4% per year simple interest on the initial deposit. T

pentagon [3]

Answer:

Part A) $\$12,220.00$

Part B) $\$12,134.08$

Part C) The simple interest investment is better than the compounded interest investment at the end of three years.

Part D) see the explanation

Step-by-step explanation:

Part A) Determine the value of the simple-interest investment at the end of three years

we know that

The simple interest formula is equal to

$A=P(1+rt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=3\ years\\ P=\$10,000\\r=7.4\%=7.4/100=0.074$

substitute in the formula above

$A=10,000(1+0.074*3)$

$A=10,000(1.222)$

$A=\$12,220.00$

Part B) Determine the value of the compound-interest investment at the end of three years

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=3\ years\\ P=\$10,000\\r=6.5\%=6.5/100=0.065\\n=4$

substitute in the formula above

$A=10,000(1+\frac{0.065}{4})^{4*3}$

$A=10,000(1.01625)^{12}$

$A=\$12,134.08$

Part C) Which investment is better over the first three years?

Compare the two investment

$\$12,134.08 < \$12,220.00$

The compounded interest investment is less than the simple interest investment

therefore

The simple interest investment is better than the compounded interest investment at the end of three years

Part D) How would you advise George to invest his money if he is unsure how long he’ll keep the money in the account?

we have

$A=10,000(1+0.074t)$ ----> simple interest formula as a function of the time t

$A=10,000(1.01625)^{4t}$ ----> compound interest formula as function of the time t

Look to the attached graph below

The red line represents the simple interest investment

The blue curve represents the compounded interest investment

After 0 years and before 4.179 years the red line is over the blue curve, that means the simple interest is better because it gives more money than the compounded interest

After that the blue curve is over the red line that means the compounded quarterly is better because it gives more money than the simple interest

therefore

I advise George to invest his money in the compounded interest investment if he will keep the money for a long time

4 0

3 years ago

Each month, Allison gets a $15 allowance and earns $100 working at the theater. She uses the expression 15x + 100y to keep track

jasenka [17]

Part A:

Expression $15x+100y$
The constants are 15 and 100
The variables are $x$ and $y$

Part B:

Expression $15x+100y$ has two terms; $15x$ and $100y$ . We know this because both have different variables attached to them

Part C:

The term $15x$ is the expression for the total earned from her allowance

8 0

3 years ago