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balu736 [363]
2 years ago
15

Please help!!!!!! Solve for x:

Mathematics
1 answer:
nordsb [41]2 years ago
8 0
A
Explanation: You want to get x by itself. So add +7 to -7 to cancel it out, do the same thing to 4.
x-7=4
+7+7
x=11
x
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Please help <br><br> 2x^2 = y^3 x=2, y=?
andriy [413]

y is also 2.

2x^2 = 8

2^3 = 8

5 0
3 years ago
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Find the value of x. Round to the<br> nearest tenth.<br> 26<br> 12<br> х<br> X=<br> = [?]
levacccp [35]

Answer:

X = 5.9 (in degree mode)

Step-by-step explanation:

Do the following:

12(tan26) = X

Plugging this into a calculator, you will get:

X = 5.9 (in degree mode)

7 0
3 years ago
a spherical balloon is deflated at a rate of 256pi/3 cm^3/sec. at what rate is the radius of the balloon changing when the radiu
Hunter-Best [27]
What you need to look for is \frac { dr }{ dt } when r=8.

Now:

Volume\quad of\quad a\quad sphere:\\ \\ V=\frac { 4 }{ 3 } \pi { r }^{ 3 }

\therefore \quad \frac { dV }{ dr } =\frac { 4 }{ 3 } \pi \cdot 3{ r }^{ 2 }=4\pi { r }^{ 2 }\\ \\ \therefore \quad \frac { dr }{ dV } =\frac { 1 }{ \frac { dV }{ dr }  } =\frac { 1 }{ 4\pi { r }^{ 2 } }

And:\\ \\ \frac { dV }{ dt } =-\frac { 256\pi  }{ 3 } \\ \\ Therefore:\\ \\ \frac { dr }{ dt } =\frac { dr }{ dV } \cdot \frac { dV }{ dt }

\\ \\ =\frac { 1 }{ 4\pi { r }^{ 2 } } \cdot -\frac { 256\pi  }{ 3 } \\ \\ =-\frac { 256 }{ 12 } \cdot \frac { \pi  }{ \pi  } \cdot \frac { 1 }{ { r }^{ 2 } }

\\ \\ =-\frac { 64 }{ 3{ r }^{ 2 } } \\ \\ When\quad r=8,\\ \\ \frac { dr }{ dt } =-\frac { 64 }{ 3\cdot { 8 }^{ 2 } } =-\frac { 1 }{ 3 } \\ \\ Answer:\quad -\frac { 1 }{ 3 } \quad cm/sec
3 0
3 years ago
Im giving 30 points pls help
gayaneshka [121]

Step-by-step explanation:

Pathagory and Theorem

a^2+b^2=c^2

(x-3)^2+(x-4)^2=6^2

expand:

2x^2-14x+25=36

2x^2-14x-11=0

x=(\sqrt{71}+7)/2

perimeter=(x-3)+(x-4)+6=2x-1

insert the value for x into 2x-1

\sqrt{71}+6=perimeter

Hope that helps :)

7 0
3 years ago
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nalin [4]

Answer:

<em>summation of five times negative three to the power of n from n equals zero to infinity</em>

Step-by-step explanation:

<u>Summation Notation </u>

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5-15+45-135+...

If we take 5 as a common factor, we have

5(1-3+9-27+...)

The parentheses contain the alternate sum/subtraction of powers of 3. The odd terms are positive, the even terms are negative, thus the exponent must be n starting from 0 or n-1 starting from 1

The summation is then represented by

\sum_{n=0}^{\infty}5(-3)^n

This corresponds with the option:

<u>summation of five times negative three to the power of n from n equals zero to infinity</u>

8 0
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