2 years ago

Find the square ofi) a+ Xii). b-y

1 answer:

7 0

Right now, x is only equal to two. Square both sides, and x^2 = 4. For some reason, if you want to take the square root of both sides, and you get x= +/- 2, ...

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Sergio [31]

Answer:

.50 C

Step-by-step explanation:

if you divide 6 by 12 you get .50

This means the cost of each apple is .50 cents.

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2 years ago

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Find the value of this expression if X = -1 and Y = -5 xy over -6

Thepotemich [5.8K]

$\frac{xy}{-6} = \frac{(-1)(-5)}{-6} = \frac{5}{-6} = -\frac{5}{6}$

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2 years ago

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8_murik_8 [283]

Answer: (3, 13)

Step-by-step explanation:

If we let the point be P, then AP:BP=2:1.

$P=\left(\frac{(2)(3)+(1)(3)}{2+1}, \frac{(2)(19)+(1)(1)}{2+1} \right)=(3, 13)$

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2 years ago

Use the quadratic formula to solve x2 + 9x + 10 = 0.<br> What are the solutions to the equation?

vampirchik [111]

Answer:

$\large\boxed{x=\dfrac{-9\pm\sqrt{41}}{2}}$

Step-by-step explanation:

$\text{The quadratic formula of}$

$ax^2+bx+c=0$

$\text{If}\ b^2-4a0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\=========================================$

$\text{We have}\ x^2+9x+10=0\\\\a=1,\ b=9,\ c=10\\\\\text{substitute:}\\\\b^2-4ac=9^2-4(1)(10)=81-40=41>0\qquad _{\text{two solutions}}\\\\\sqrt{b^2-4ac}=\sqrt{41}\\\\x=\dfrac{-9\pm\sqrt{41}}{2(1)}=\dfrac{-9\pm\sqrt{41}}{2}$

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The most simplified version of it is 49/50

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Find the square ofi) a+ Xii). b-y​

Find the square ofi) a+ Xii). b-y