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3 years ago

Help plz???? never learned this

Mathematics

2 answers:

stira [4]3 years ago

8 0

suppelementary angles are angles that add to 180

remember that a straight line is 180 degrees so some angles that are supplementary are 1 and 2, 5 and 6, 1 and 5, 6 and 2, 3 and 7, 4 and 8, 7 and 8, 3 and 4

vertical angles are across from each other when 2 lines cross, they are like 5 and 2, 6 and 1, 7 and 4, 8 and 3

Mice21 [21]3 years ago

4 0

The supplementary angles are 1 and 5 , 6 and 2 because they add up to 180.

And the vertical angles are 1 and 6, 2 and 5 which makes the pairs congruent.

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Which of the following is an informal proof of the given conjecture? Conjecture: All squares are similar

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beaus recipefor granola bars calls for 3 1/2 cups of oatmeal. he only have 1/6 cup scoop.how many scoops of oatmeal will he need

Stells [14]

<h2>Answer:</h2>

The number of scoops of oatmeal he will need for the recipe is:

21 scoops.

<h2>Step-by-step explanation:</h2>

It is given that:

Beaus recipe for granola bars calls for 3 1/2 cups of oatmeal.

i.e. the cups of oatmeal required is:

$3\dfrac{1}{2}\ cups=\dfrac{3\times 2+1}{2}\ cups$

i.e.

$\dfrac{7}{2}\ \text{cups\ of\ oatmeal\ is\ required}$

Also, he has:

$\dfrac{1}{6}\ \text{cup scoop}$

This means that:

$\text{Number of scoops of oatmeal he need}=\dfrac{\text{Number of cups of oatmeal}}{\text{Number of cup scoop he has}}\\\\i.e.\\\\\text{Number of scoops of oatmeal he need}=\dfrac{\dfrac{7}{2}}{\dfrac{1}{6}}\\\\i.e.\\\\\text{Number of scoops of oatmeal he need}=\dfrac{7\times 6}{1\times 2}\\\\i.e.\\\\\text{Number of scoops of oatmeal he need}=21\ \text{scoops}$

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3 years ago

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19) Liam has a free throw percentage of 0.64. If he takes 6 free throw shots in a game, what is the probability that he will mak

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3 years ago

Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 75.6 Mbp

olga55 [171]

Answer:

a) 59.98

b) 2.99

c) 2.99

d) Significantly High

Step-by-step explanation:

Part a)

Highest speed measured = x = 75.6 Mbps

Average/Mean speed = $\overline{x}$ = 15.62 Mbps

Standard Deviation = s = 20.03 Mbps

We need to find the difference between carrier's highest data speed and the mean of all 50 data speeds i.e. x - $\overline{x}$

x - $\overline{x}$ = 75.6 - 15.62 = 59.98 Mbps

Thus, the difference between carrier's highest data speed and the mean of all 50 data speeds is 59.98 Mbps

Part b)

In order to find how many standard deviations away is the difference found in previous part, we divide the difference by the value of standard deviation i.e.

$\frac{59.98}{20.03}=2.99$

This means, the difference is 2.99 standard deviations or in other words we can say, the Carrier's highest data speed is 2.99 standard deviations above the mean data speed.

Part c)

A z score tells us that how many standard deviations away is a value from the mean. We calculated the same in the previous part. Performing the same calculation in one step:

The formula for the z score is:

$z=\frac{x-\overline{x}}{s}$

Using the given values, we get:

$z=\frac{75.6-15.62}{20.03}=2.99$

Thus, the Carriers highest data is equivalent to a z score of 2.99

Part d)

The range of z scores which are neither significantly low nor significantly high is -2 to + 2. The z scores outside this range will be significant.

Since, the z score for carrier's highest data speed is 2.99 which is well outside the given range, i.e. greater than 2, we can conclude that the carrier's highest data speed is significantly higher.

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3 years ago