All categories

2 years ago

Find the slope of the line passing through the points (-7 ,-7) and (-3,6)

Mathematics

1 answer:

ycow [4]2 years ago

6 0

Answer:

14/4 or 7/2

Step-by-step explanation:

6 - (-7)

---------

-3 - (-7)

When you subtract a - its really just adding

You might be interested in

PLEASE HELP WILL MARK YOU BRAINLIEST!!! 50 POINTS’

photoshop1234 [79]

Answer:

I can’t answer

Step-by-step explanation:

Pls take a state photo I can’t tell if it is a rectangle or a polygon

6 0

3 years ago

Read 2 more answers

Round 7.4521 to 2 significant figures

Troyanec [42]

7.5 would be my best guess

5 0

3 years ago

Read 2 more answers

The segments represent roads in a town, measured in miles. Theo drove from the post office to the grocery store. How many miles

Ivahew [28]

Answer:

16 miles

Step-by-step explanation:

The graph is counting by 2, and there are 8 spaces between the Grocery store and the post office. 8(2) = 16

6 0

3 years ago

Read 2 more answers

Plz help easy math !!

Dima020 [189]

The answer is A B and E

7 0

3 years ago

Read 2 more answers

Prove that a triangle with the sides a - 1 cm to root under a

vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm

Hence,

${AB}^2 = (a -1)^2$

Now We know that

$(a- b)^2 = a^2+b^2 - 2ab$

So;

${AB}^2= a^2 + 1^2 -2\times a \times1$

${AB}^2 = a^2 + 1 -2a$

Now;

${BC}^2 = (2\sqrt{a})^2= 4a$

Also;

${CA}^2 = (a + 1)^2$

Now We know that

$(a+ b)^2 = a^2+b^2 + 2ab$

${CA}^2= a^2 + 1^2 +2\times a \times1$

${CA}^2 = a^2 + 1 +2a$

${CA}^2 = AB^2 + BC^2$

[By Pythagoras theorem]

$a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a$

Hence, ${CA}^2 = AB^2 + BC^2$

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

4 0

3 years ago