Median and IQR are the most appropriate measures of center and spread for this data set.
<h3>Why are
Median and IQR the most appropriate?</h3>
Among the 3 central tendencies that includes the mean, median and mode; the median is the better measure because of the followings:
- Mean is affected by extreme values
- Mean is not correct if more outliers are present
- Mean may not represent the nature of the data whether skewed right or left.
Also, the median as the middle entry is not affected by extreme items or outliers, so the median is better than mean,
Furthermore, for the measure of spread, the IQR is better since extreme items will show higher std deviation and also some outliers mislead.
Therefore, Option B is correct.
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Answer:
Step-by-step explanation:
80.08 = (8 * 101) + (8 * 1/102)
80.08 = (8 * 10) + (8 * 1/100)
80.08 = 80 + 8/100
80.08 = 80 + 0.08
3.25 is rounded to the nearest thousandth
Using the binomial distribution, there is a 0.3474 = 34.74% probability of getting one wrong number.
<h3>What is the binomial distribution formula?</h3>
The formula is:
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
For this problem, the values of the parameters are given by:
p = 0.15, n = 10.
The probability of getting one wrong number is P(X = 1), hence:
P(X = 1) = C(10,1) x (0.15)¹ x (0.85)^9 = 0.3474
0.3474 = 34.74% probability of getting one wrong number.
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Use the communicative property of addition to switch to order and you get
13 - 5, so the answer is 8, or k = 8
OR
-5 + 13 = k
Combine like terms
8 = k
or
k = 8<span />