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Arturiano [62]
1 year ago
13

Can someone please give me the (Answers) to this? ... please ... I need help….

Mathematics
2 answers:
enot [183]1 year ago
7 0

7. Triangles KJL similar to Triangle QPR

         \frac{KJ}{LJ} =\frac{QP}{RP} \\\frac{KJ}{28} =\frac{33}{42} \\KJ = \frac{33}{42} *28 =22

8. Triangles KML similar to Triangle VTU

       \frac{UT}{UV} =\frac{LM}{LK} \\\frac{UT}{60} =\frac{117}{130} \\UT =\frac{117}{130} *60\\UT=54

Last question: Triangle CUB similar to TUS

  • if both triangles are similar then the side lengths are equally  

     proportional

  • For the picture, we see that TU is three times as long as CU
  • therefore SU is three times as long as BU, and since SU is 12 then BU is 4. Therefore SB is 8
Alja [10]1 year ago
6 0

Answer:

above is the answer to the question

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arsen [322]

Answer:

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Step-by-step explanation:

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Each term in the second factor is multiplied by each term in the first factor

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Afina-wow [57]

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Hope this helps!

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