we can always find the x-intercept of any equation by simply setting y = 0, so let's do so
![\bf 4x+3y=36\implies 4x+3(\stackrel{y}{0})=36\implies 4x=36\implies x=\cfrac{36}{4}\implies x = 9 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill (9~~,~~0)~\hfill](https://tex.z-dn.net/?f=%5Cbf%204x%2B3y%3D36%5Cimplies%204x%2B3%28%5Cstackrel%7By%7D%7B0%7D%29%3D36%5Cimplies%204x%3D36%5Cimplies%20x%3D%5Ccfrac%7B36%7D%7B4%7D%5Cimplies%20x%20%3D%209%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20%289~~%2C~~0%29~%5Chfill)
Answer:
11/2
Step-by-step explanation:

when,

Now substitute the value we get,

Answer:
3
Step-by-step explanation:
<span>Old Surface Area = 202 ft^2
New Surface Area = 1818 ft^2
Notice we have this ratio:
(new area)/(old area) = 1818/202 = 9
and how 3^2 = 9. This is no coincidence.
The old surface area is multiplied by 3^2 = 9 to get the new surface area
.
If you asked "What would the surface area of the prism be if each dimension were quadrupled?"
, then you would multiply the old surface area by 4^2 = 16 to get the new surface area So really thats how you would solve that </span><span />