The square root of 49 is the number, which multiplied by itself, is 49. In other words, the square of this number equals forty-nine. If you have been looking for square root of forty-nine, then you are right here, too. On this page you can also find what the parts of √49 are called, and in addition to the terminology of √49, we also have a calculator you don’t want to miss. Read on to learn everything about the sqrt 49.
this should help u answer it
Answer:
No Pedro's logic does not make any sense
Step-by-step explanation:
It depends on how it is graph.
D
When you add 2+3 which equals 5 so it’ll be y=5x-7. And plug in y into the other equation. 5x-7-5x+8=0. -7-8=0, -7-8 =-1 therefore there is no solution because-7-8= -1 not 0.
In order to accurately answer any fraction, it is best to have a common denominator (bottom of the fraction)
Since in
![\frac{45}{100}](https://tex.z-dn.net/?f=%20%5Cfrac%7B45%7D%7B100%7D%20)
, 100 is the denominator, you need to make the other fraction with the same denominator
So Multiply
![\frac{6}{10}](https://tex.z-dn.net/?f=%20%5Cfrac%7B6%7D%7B10%7D%20)
by <u />
![\frac{6}{10} * \frac{10}{10} = \frac{60}{100}](https://tex.z-dn.net/?f=%20%5Cfrac%7B6%7D%7B10%7D%20%2A%20%5Cfrac%7B10%7D%7B10%7D%20%3D%20%20%5Cfrac%7B60%7D%7B100%7D%20)
So
![\frac{45}{100} < \frac{60}{100}](https://tex.z-dn.net/?f=%20%5Cfrac%7B45%7D%7B100%7D%20%3C%20%5Cfrac%7B60%7D%7B100%7D%20)
or
![\frac{45}{100} < \frac{6}{10}](https://tex.z-dn.net/?f=%20%5Cfrac%7B45%7D%7B100%7D%20%3C%20%5Cfrac%7B6%7D%7B10%7D%20)
You can do this another way which involves the opposite way of multiplying which is by dividing
Since you have to get a common denominator to measure accurately no matter what, you can divide
One thing to know is that when dividing fractions, both the denominator and numerator have to be divided by a factor to be divided and result in a whole number
![\frac{45}{100}](https://tex.z-dn.net/?f=%20%5Cfrac%7B45%7D%7B100%7D%20)
÷
![\frac{5}{5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B5%7D%20)
=
![\frac{9}{20}](https://tex.z-dn.net/?f=%20%5Cfrac%7B9%7D%7B20%7D%20)
So just have to multiple
![\frac{6}{10} by \frac{2}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B6%7D%7B10%7D%20by%20%5Cfrac%7B2%7D%7B2%7D%20)
![\frac{6}{10} * \frac{2}{2} = \frac{12}{20}](https://tex.z-dn.net/?f=%20%5Cfrac%7B6%7D%7B10%7D%20%2A%20%5Cfrac%7B2%7D%7B2%7D%20%3D%20%5Cfrac%7B12%7D%7B20%7D%20)
![\frac{9}{20} < \frac{12}{20}](https://tex.z-dn.net/?f=%20%5Cfrac%7B9%7D%7B20%7D%20%3C%20%5Cfrac%7B12%7D%7B20%7D%20)
![\frac{9}{20}](https://tex.z-dn.net/?f=%20%5Cfrac%7B9%7D%7B20%7D%20)
⇒
![\frac{45}{100}](https://tex.z-dn.net/?f=%20%5Cfrac%7B45%7D%7B100%7D%20)
![\frac{12}{20}](https://tex.z-dn.net/?f=%20%5Cfrac%7B12%7D%7B20%7D%20)
⇒
![\frac{6}{10}](https://tex.z-dn.net/?f=%20%5Cfrac%7B6%7D%7B10%7D%20)
The results are the same
![\frac{45}{100} < \frac{6}{10}](https://tex.z-dn.net/?f=%20%5Cfrac%7B45%7D%7B100%7D%20%3C%20%5Cfrac%7B6%7D%7B10%7D%20)
Again
![\frac{6}{10}](https://tex.z-dn.net/?f=%20%5Cfrac%7B6%7D%7B10%7D%20)
is greater than