Answer:
Height of the taller building is 63.5ft
Step-by-step explanation:
Kindly find attached rough sketch of the problem for your reference.
Let the small building be A and the taller building be B
From the sketch the two buildings form a right angle triangle
We can solve for x which is the height of the taller building relative to the small building using
SOH CAH TOA
Applying TOA we have
Tan θ= opposite/adjacent
Tan 42°= x/35
x= Tan 42*35
x= 0.9*35
x= 31.5ft
Hence the height of the taller building is = x+height of small building = 31.5+32= 63.5ft
Answer: The variable represents the number of packages of corn.
Step-by-step explanation:
1. You have the following expression given in the problem:
2. Then, if the expression represents the cost of the corn for a number of packages, then the price of a package (which is $3.59) must be multiplied by the number of packages (which must be represented by the variable ).
3. Therefore, you can conclude that the variable represents the number of packages of corn.
Answer:
424 cm²
Step-by-step explanation:
The figure is composed of a square and a trapezium on top
A of square = 18² = 324 cm²
A of trapezium = h (b₁ + b₂ )
where h is the perpendicular height and b₁, b₂ the parallel bases
Here h = 8, b₁ = 18 and b₂ = 7 , then
A = 0.5 × 8 × (18 + 7) = 4 × 25 = 100 cm²
Area of hexagonal park = 324 + 100 = 424 cm²