Two buildings are 35 feet apart. The angle of elevation from the top of the smaller building to the top of the taller building i
s 42˚. The smaller building is 32 feet high. Find the height of the taller building.
1 answer:
Answer:
Height of the taller building is 63.5ft
Step-by-step explanation:
Kindly find attached rough sketch of the problem for your reference.
Let the small building be A and the taller building be B
From the sketch the two buildings form a right angle triangle
We can solve for x which is the height of the taller building relative to the small building using
SOH CAH TOA
Applying TOA we have
Tan θ= opposite/adjacent
Tan 42°= x/35
x= Tan 42*35
x= 0.9*35
x= 31.5ft
Hence the height of the taller building is = x+height of small building = 31.5+32= 63.5ft
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