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2 years ago

Please help me with this following problem

Mathematics

1 answer:

Volgvan2 years ago

7 0

Answer:

a - 30.2

b - 271.8

Step-by-step explanation:

60/4=15

60/3=20

9+6.45+2.4+8.15+4.2=30.2

30.2x9=271.8

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How would you solve for side a? Pythagorean theorem, cause if that's the case wouldn't

Yuri [45]

The angle is 127°, so the Pythagorean theorem does not apply.

Generally, you would use the Law of Cosines to solve for the third side when given two sides and the angle between them.

EF^2 = 7^2 +15^2 -2*7*15*cos(127°)
EF ≈ √(400.3812) ≈ 20.00953

My guess is that you're expected to use 20 for the length of the 3rd side.

By Heron's formula, s = (7 +15 +20)/2 = 21

Area = √(21*(21 -7)*(21 -15)*(21 -20)) = √(21*14*6*1) = √1764 = 42 . . . . yd^2

_____
More directly,
.. Area = (1/2)*7*15*sin(127°) ≈ 41.928 . . . . yd^2

3 0

4 years ago

Find the inverse of the matrix <img src="https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%26-2%5C%5C-10%269%5C%5C

valentinak56 [21]

Answer:

The answer is (b)

Step-by-step explanation:

* Lets check how to find the inverse of the matrix,

its dimensions is 2 × 2

* To know if the inverse of the matrix exist find the determinant

- If its not equal 0, then it exist

* How to find the determinant

- It is the difference between the multiplication of

the diagonals of the matrix

Ex: If the matrix is $\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]$

its determinant = ad - bc

- After that lets swap the positions of a and d, put negatives

in front of b and c, and divide everything by the determinant

- The inverse will be $\left[\begin{array}{ccc}\frac{d}{ad-bc} &\frac{-b}{ad-bc}\\\frac{-c}{ad-bc} &\frac{a}{ad-bc}\end{array}\right]$

* Lets do that with our problem

∵ The determinant = (9 × 9) - (-2 × -10) = 81 - 20 = 61

- The determinant ≠ 0, then the inverse is exist

∴ The inverse is $\frac{1}{61}\left[\begin{array}{ccc}9&2\\10&9\end{array}\right]$ =

$\left[\begin{array}{ccc}\frac{9}{61}&\frac{2}{61}\\\frac{10}{61} &\frac{9}{61}\end{array}\right]$

* The answer is (b)

7 0

3 years ago

Three pounds of dried cherries cost $15.90, 5 pounds of dried cherries cost $26.50, and 9 pounds of dried cherries cost $47.70.

quester [9]

Answer:

The equation which gives the total cost y of x pounds of dried cherries is $y=5.3x$

Step-by-step explanation:

Given:

Cost of 3 pounds of dried cherries = $15.90

Cost of 5 pounds of dried cherries = $26.50

Cost of 9 pounds of dried cherries = $47.70

Let Number of of pounds of dried cherries be 'x'

Let Total Cost be denoted by 'y'

We need to find the equation for total cost y for x pounds of dried cherries.

First we will find the cost of each pound of dried cherries.

Now we know that;

3 pounds of dried cherries = $15.90

1 pound of dried cherries = Cost of 1 pounds of dried cherries

Hence By using Unitary method we get;

Cost of 1 pounds of dried cherries = $\frac{15.90}{3} = \$5.3$

Total Cost of dried cherries is equal to Number of of pounds of dried cherries multiplied by Cost of 1 pounds of dried cherries.

framing in equation form we get;

$y=5.3x$

Hence The equation which gives the total cost y of x pounds of dried cherries is $y=5.3x$

3 0

3 years ago

Write the appropriate direct variation when x=6 and y=15

laiz [17]

Did that come with a image?

6 0

3 years ago

Simplify the expression:Two-thirds divided by (negative 4) minus (one-sixth minus StartFraction 8 over 6 EndFraction)

disa [49]

Answer:

the answer is 1

Step-by-step explanation:

i just answered that question and i got it right

7 0

3 years ago

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