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kumpel [21]
2 years ago
6

Please help me with this following problem

Mathematics
1 answer:
Volgvan2 years ago
7 0

Answer:

a - 30.2

b - 271.8

Step-by-step explanation:

60/4=15

60/3=20

9+6.45+2.4+8.15+4.2=30.2

30.2x9=271.8

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Simplify 6 to the 5th power over 7 to the 3rd power times 2
Anon25 [30]
My answer -

<span>1. Use symbols (not words) to express quotient
 

2. Use exponent symbol (^) to denote exponents

3. Just write out question number, question, and choices. No need for extra information (such as points). Also, don't leave blank lines between choices. This extraneous that we don't need just makes your whole question very very long, and means a lot of scrolling on our part.
 

4. You should only post 2 or 3 questions at a time.


1) (6x^3 − 18x^2 − 12x) / (−6x) = −x^2 + 3x + 2 ----> so much simpler to read !

2) (d^7 g^13) / (d^2 g^7) = d^(7−2) g^(13−7) = d^5 g^6 ----> much easier to read !

3) (4x − 6)^2 = 16x^2 − 24x − 24x + 36 = 16x^2 − 48x + 36

4) (x^2 / y^5)^4 = (x^2)^4 / (y^5)^4 = x^8 / y^20

5) (3x + 5y)(4x − 3y) = 12x^2 − 9xy + 20xy − 15y^2 = 12x^2 + 11xy − 15y^2

6) (3x^3y^4z^4)(2x^3y^4z^2) = (3*2) x^(3+3) y^(4+4) z^(4+2) = 6 x^6 y^8 z^6

7) 5x + 3x^4 − 7x^3 ----> Fourth degree trinomial

8) (5x^3 − 5x − 8) + (2x^3 + 4x + 2) = 7x^3 − x − 6

9) (x − 1) + (2x + 5) − (x + 3) = x + 1

10) (−4g^8h^5k^2)0(hk^2)^2 = 0 (anything multiplied by 0 = 0)
or.. (−4g^8h^5k^2)^0(hk^2)^2 = 1 (h^2 (k^2)^2) = h^2 k^4

Last question shows why it is so important to use proper symbols (such as ^ to indicate exponents). Without such symbols, I could not tell if the 0 was an actual number and part of multiplication, of if 0 was an exponent of the expression preceding it.


P.S

Glad to help you have an AWESOME!!! day :)
</span>
6 0
3 years ago
1. Flight 202's arrival time is normally distributed with a mean arrival time of 4:30
Bezzdna [24]

Answer:

Step-by-step explanation:

1) Let the random time variable, X = 45min; mean, ∪ = 30min; standard deviation, α = 15min

By comparing P(0 ≤ Z ≤ 30)

P(Z ≤ X - ∪/α) = P(Z ≤ 45 - 30/15) = P( Z ≤ 1)

Using Table

P(0 ≤ Z ≤ 1) = 0.3413

P(Z > 1) = (0.5 - 0.3413) = 0.1537

∴ P(Z > 45) = 0.1537

2)  By compering (0 ≤ Z ≤ 15) ( that is 4:15pm)

P(Z ≤ 15 - 30/15) = P(Z ≤ -1)

Using Table

P(-1 ≤ Z ≤ 0) = 0.3413

P(Z < 1) = (0.5 - 0.3413) = 0.1587

∴ P(Z < 15) = 0.1587

3) By comparing P(0 ≤ Z ≤ 60) (that is for 5:00pm)

P(Z ≤ 60 - 30/15) = P(Z ≤ 2)

Using Table

P(0 ≤ Z ≤ 1) = 0.4772

P(Z > 1) = (0.5 - 0.4772) = 0.0228

∴ P(Z > 60) = 0.0228

6 0
3 years ago
You buy two packages of almonds. One package is 10.47 kg and the other is 8.23 kg. What is the difference?
fomenos

Answer:

2.04 kg

Step-by-step explanation:

5 0
3 years ago
i bought 6 apples for0.30 dollars each and 5 oranges for 0.40 dollars each. how much did i spend ? write an equation then solve​
katovenus [111]

Answer:

3.8

Step-by-step explanation:

if the apples are 0.30 cents each then you multiply .3 X 6 and you get 1.8 because 1 apple is .30 cents you want to know how much is 6.

Next you pay .40 cents each for 5 oranges so .4 X 5 which is 2. And once again one orange is .40 cents so you multiply that by 5 to see the price of 5 oranges

Now you add the 1.8 to 2 and get 3.8

Now for the equation you just need to plug in what you did so...

(0.3 X 6) + (0.40 X 5) =  3.8

Glad i could help :)

7 0
3 years ago
The United States five-dollar bill are 155.956 mm long and 66.294 wide. A stack of these bills fits inside a 156 x 66.3 x 66.3 m
maxonik [38]

Answer:

A) $5 × 25 = $75

B) 37.69%

Step-by-step explanation:

The dimension of five dollar bill:

Length = 155.956mm

Width = 66.294

Volume of box being occupied by 5 dollar bill = 258,473.68mm^3

Dimension of box :

156 x 66.3 x 66.3 mm

If volume of the 5—dollar bill is 258,473.68mm^3

Then, the Thickness of the five dollar stack equals :

Volume = Length × width × height

258,473.68mm^3 = 155.956mm × 66.294 × height

258,473.68 = 10338.947064 × h

h = (258473.68/10338.947064)

h = 25.000000003288 = 25

Therefore, the amount of money in the box is:

$5 × 25 = $75

Percentage of box volume taken up by $5 bill

Volume of the box:

156 x 66.3 x 66.3 mm = 685727.6399mm^3

Volume of box being occupied by 5 dollar bill = 258,473.68mm^3

(258,473.68 / 685727.6399) × 100

=37.69%

4 0
3 years ago
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