The coordinates of the new rectangle formed after transformation are; A'(3, -1); B'(6, -1); C'(6, 4); D'(3, 4)
<h3>How to carry out rotational transformation?</h3>
We are told that the original rectangle which I labelled ABCD in the attached image is rotated 90° clockwise about the origin.
Now, from the translation of Rectangle ABCD into A'B'C'D' using the transformation rule in the question, the new coordinates are;
A'(3, -1)
B'(6, -1)
C'(6, 4)
D'(3, 4)
Read more about Rotational Transformation at; brainly.com/question/4289712
#SPJ1
Answer:
option 1
Step-by-step explanation:
y = 3x + 3 ie 3x -y +3 =0 a1= 3 , b1=-1 , c1=3
y = -2x + 3 ie -2x -y+3 = 0 a2=-2 , b2=-1 , c2=3
on comparing the ratios ,
a1/a2 = 3/2
b1/b2 = -1/-1= 1/1 =1/1= 1
a1/a2 ≠ b1/b2
therefore the pair of linear equations will have exactly one solution
mark me as the brainliest...
Answer:
lines that intersect each other like a cross
Answer:
Step-by-step explanation:
The altitude to the hypotenuse of a right triangle create two smaller triangles, all of which are similar to the original. This means corresponding sides are proportional.
3. Using the above relationship, ...
short-side/hypotenuse = 8/y = y/(8+23)
y^2 = 8·31
y = 2√62
__
long-side/hypotenuse = z/(8+23) = 23/z
z^2 = 23·31
z = √713
__
short-side/long-side = 8/x = x/23
x^2 = 8·23
x = 2√46
_____
4. The picture is fuzzy, but we think the lengths are 25 and 5. If they're something else, use the appropriate numbers. Using the same relations we used for problem 3,
y = √(5·25) = 5√5 . . . . . . . = √(short segment × hypotenuse)
z = √(20·25) = 10√5 . . . . . = √(long segment × hypotenuse)
x = √(5·20) = 10 . . . . . . . . . = √(short segment × long segment)
Like terms" are terms whose variables (and their exponents such as the 2 in x2) are the same. In other words, terms that are "like" each other. Note: the coefficients (the numbers you multiply by, such as "5" in 5x) can be different.
