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charle [14.2K]
3 years ago
14

Which value is a solution to the equation 8c=64 c=6 c=7 c=8 c=9

Mathematics
2 answers:
Olegator [25]3 years ago
7 0

Step-by-step explanation:

c=8

hope it helps.....,

lutik1710 [3]3 years ago
6 0

Answer:

c = 8

Step-by-step explanation:

8 x 8 = 64

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For 2 cups of flour for every 3 cups of milk. If u use 6 cups of flour, how many cups of milk do you need?
raketka [301]

Answer:

9 cups of milk

Step-by-step explanation:

2 cups of flour - 3 cups of milk

4- cups of flower - 6 cups of milk

6 cups of flower - 9 cups of milk

Please mark brainliest and have a great day!

5 0
3 years ago
Read 2 more answers
Solve x^2 + 4x + 8 = 0
Mkey [24]

Answer:

x = -2 + 2 i or x = -2 - 2 i

Step-by-step explanation:

Solve for x:

x^2 + 4 x + 8 = 0

Subtract 8 from both sides:

x^2 + 4 x = -8

Add 4 to both sides:

x^2 + 4 x + 4 = -4

Write the left hand side as a square:

(x + 2)^2 = -4

Take the square root of both sides:

x + 2 = 2 i or x + 2 = -2 i

Subtract 2 from both sides:

x = -2 + 2 i or x + 2 = -2 i

Subtract 2 from both sides:

Answer:  x = -2 + 2 i or x = -2 - 2 i

8 0
3 years ago
Which of these is an example of employment ?
Solnce55 [7]
A job is an example of employment
7 0
3 years ago
Find the equation of a line that is perpendicular to x+y=8 and passes through the point (8, 10).
ArbitrLikvidat [17]

Answer:

Y = -x + 2

Step-by-step explanation:

y = -x + 8

y = 1x + b

10 = 8 + b

b = 2

6 0
3 years ago
Read 2 more answers
A skier has decided that on each trip down a slope, she will do 3 more jumps than before. On her first trip she did 5 jumps. Der
taurus [48]
Since we are already given the amount of jumps from the first trial, and how much it should be increased by on each succeeding trial, we can already solve for the amount of jumps from the first through tenth trials. Starting from 5 and adding 3 each time, we get: 5 8 (11) 14 17 20 23 26 29 32, with 11 being the third trial.

Having been provided 2 different sigma notations, which I assume are choices to the question, we can substitute the initial value to see if it does match the result of the 3rd trial which we obtained by manual adding.

Let us try it below:

Sigma notation 1:

  10
<span>   Σ (2i + 3)
</span>i = 3

@ i = 3

2(3) + 3
12

The first sigma notation does not have the same result, so we move on to the next.

  10
<span>   Σ (3i + 2)
</span><span>i = 3
</span>
When i = 3; <span>3(3) + 2 = 11. (OK)
</span>
Since the 3rd trial is a match, we test it with the other values for the 4th through 10th trials.

When i = 4; <span>3(4) + 2 = 14. (OK)
</span>When i = 5; <span>3(5) + 2 = 17. (OK)
</span>When i = 6; <span>3(6) + 2 = 20. (OK)
</span>When i = 7; 3(7) + 2 = 23. (OK)
When i = 8; <span>3(8) + 2 = 26. (OK)
</span>When i = 9; <span>3(9) + 2 = 29. (OK)
</span>When i = 10; <span>3(10) + 2 = 32. (OK)

Adding the results from her 3rd through 10th trials: </span><span>11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 172.
</span>
Therefore, the total jumps she had made from her third to tenth trips is 172.


3 0
3 years ago
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