2 years ago

Can you guys are help me please, thank you

Mathematics

1 answer:

Tomtit [17]2 years ago

4 0

Do you know what a transformation is

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Solve the simltaneous equtions: 3x - 4y = 18 9x + 2y = 12

hichkok12 [17]

Answer:

x=2 y= -3

Step-by-step explanation:

3 0

3 years ago

Eliminate the parameter t. Then use the rectangular equation to sketch the plane curve represented by the given parametric equat

____ [38]

Answer:

$9x^2+4y^2=36$

Step-by-step explanation:

We are given that

$x=2cos t$

$y=3 sin t$

$0\leq t\leq 2\pi$

$cost=\frac{x}{2}$

$sint=\frac{y}{3}$

$sin^2 t+cos^2 t=(\frac{x}{2})^2+(\frac{y}{3})^2$

$1=\frac{x^2}{4}+\frac{y^2}{9}$

By using the formula

$sin^2\theta+cos^2\theta=1$

$1=\frac{9x^2+4y^2}{36}$

$9x^2+4y^2=36$

4 0

3 years ago

To those who need points 4-9+5/6*33

son4ous [18]

Answer:

22.5

Step-by-step explanation:

$4-9+\dfrac{5}{6}\cdot 33= \\\\\\4-9+27.5= \\\\\\-5+27.5= \\\\\\22.5$

Hope this helps!

8 0

4 years ago

Read 2 more answers

Math help mee plzzzzzz THERE IS A ATTACHMENT SO WAIT AT LEAST 30 SECONDS PLZZZZ

KengaRu [80]

1. A
2. A, C and E
Hope it helps!

7 0

4 years ago

Solve 4 over x minus 4 equals the quantity of x over x minus 4, minus four thirds for x and determine if the solution is extrane

Vinil7 [7]

I'm thinking this is what the problem looks like: $\frac{4}{x-4}= \frac{x}{x-4}- \frac{4}{3}$ . The first thing to do is to move the $\frac{x}{x-4}$ over to the other side because it has a common denominator with the other side. Doing that and at the same time combining them over their common denominator looks like this: $\frac{4-x}{x-4}= -\frac{4}{3}$ . The best way to solve for x now is to cross-multiply to get 3(4-x)=-4(x-4). Distributing through the parenthesis is 12 - 3x = -4x + 16. Solving for x gives us x = 4. Of course when we sub a 4 back in for x we get real problems, don't we? Dividing by zero breaks every rule in math that there ever was! So, yes, the solution is extraneous.

6 0

3 years ago