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1 answer:
Answer:
A. 2x(x+1)(x-6); 0, -1, 6
Step-by-step explanation:
The zeros are the values of x that make the factors zero. That is, for binomial factors, they are the opposite of the constant in the binomial factor. For example, the factor (x+1) will be zero when x = -1, so that -1+1 = 0.
This observation eliminates choices B and C.
__
The product of binomial factors looks like this:
(x +a)(x +b) = x² +(a+b)x +ab . . . . . x-coefficient is (a+b)
Once 2x is factored from the given polynomial, the resulting quadratic is ...
x^2 -5x -6
This means the sum of the constants in the binomial terms must be -5. That will only be the case for choice A.
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Answer:
14.28% of individual adult females have weights between 75 kg and 83 kg.
92.82% of the sample means are between 75 kg and 83 kg.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean and standard deviation
, a large sample size can be approximated to a normal distribution with mean
and standard deviation
.
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Assume that weights of adult females are normally distributed with a mean of 79 kg and a standard deviation of 22 kg. This means that .
What percentage of individual adult females have weights between 75 kg and 83 kg?
This percentage is the pvalue of Z when subtracted by the pvalue of Z when
. So:
X = 83
has a pvalue of 0.5714.
X = 75
has a pvalue of 0.4286.
This means that 0.5714-0.4286 = 0.1428 = 14.28% of individual adult females have weights between 75 kg and 83 kg.
If samples of 100 adult females are randomly selected and the mean weight is computed for each sample, what percentage of the sample means are between 75 kg and 83 kg?
Now we use the Central Limit THeorem, when . So
X = 83
has a pvalue of 0.9641.
X = 75
has a pvalue of 0.0359.
This means that 0.9641-0.0359 = 0.9282 = 92.82% of the sample means are between 75 kg and 83 kg.
Hello!
<em><u>Answer:</u></em>
<em><u>x=8</u></em>
<em><u>*The answer must have a positive sign.*</u></em>
Step-by-step explanation:
Distributive property: a(b+c)=ab+ac
First, you divide by 3 from both sides of an equation.
And then, you simplify. Then you can also divide by the numbers too.
Next, you subtract by 4 from both sides of an equation.
And finally, simplify and solve. You subtract by the numbers.
Final answer: →
Hope this helps!
Thanks!
-Charlie
Have a great day!
:)
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