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suter [353]
3 years ago
9

The quotient is 71 2/3 what is the divisor?

Mathematics
1 answer:
Lina20 [59]3 years ago
3 0
There's no way to know that until you tell us the dividend too. It could be literally ANY number.
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24 - c/12 = -89 what is x
VLD [36.1K]

Answer:

24

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c

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1356

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1356

Step-by-step explanation:

5 0
3 years ago
cheryl is organizing her movie collection. if each movie case is 3/4 inch wide, how many movies can fit on a shelf 5 feet wide?
xxTIMURxx [149]

Answer:8

Step-by-step explanation:

8 0
4 years ago
Geometry help please! Match the reasons with the statements
Alex73 [517]
  • Given ⇔  1. ∠PRS and ∠VUW are supplementary
  • Angles forming a linear pair sum of 180°  ⇔ 3. ∠PRS + ∠SRU = 180°
  • Definition of Supplementary angle   ⇔ 2. ∠PRS + ∠VUW = 180°
  • Transitive property of equality  ⇔ 4 . ∠PRS + ∠VUW  = ∠PRS + ∠SRU
  • Algebra  ⇔ 5. ∠VUW =  ∠SRU
  • Converse of Corresponding angle Postulate ⇔ Line TV || Line QS

<u>Step-by-step explanation:</u>

Here we have , ∠PRS and ∠VUW are supplementary . We need to complete the proof of TV || QS , with matching the reasons with statements .Let's do this :

  • Given ⇔  1. ∠PRS and ∠VUW are supplementary
  • Angles forming a linear pair sum of 180°  ⇔ 3. ∠PRS + ∠SRU = 180°
  • Definition of Supplementary angle   ⇔ 2. ∠PRS + ∠VUW = 180°
  • Transitive property of equality  ⇔ 4 . ∠PRS + ∠VUW  = ∠PRS + ∠SRU
  • Algebra  ⇔ 5. ∠VUW =  ∠SRU
  • Converse of Corresponding angle Postulate ⇔ Line TV || Line QS

Above mentioned are  , are the statements matched with expressions on right hand side (RHS)  .

  • The Corresponding Angles Postulate states that, when two parallel lines are cut by a transversal , the resulting corresponding angles are congruent .
  • The converse states: If corresponding angles are congruent, then the lines cut by the transversal are parallel.
5 0
3 years ago
Please help me answer this question(#4)
igomit [66]

Answer:

It is 18 because if you look at the side the small one says 3 the big one says 6 so if you multiply the 9 square feet by 2 thats your answer

7 0
3 years ago
Read 2 more answers
Suppose that x is a binomial random variable with n=5, p=. 3,and q=. 7.1. Write the binomial formula for this situation and list
Radda [10]

Answer:

P(X = x) = C_{5,x}.(0.3)^{x}.(0.7)^{5-x}

Possible values of x: Any from 0 to 5.

P(X = 0) = C_{5,0}.(0.3)^{0}.(0.7)^{5-0} = 0.16807

P(X = 1) = C_{5,1}.(0.3)^{1}.(0.7)^{5-1} = 0.36015

P(X = 2) = C_{5,2}.(0.3)^{2}.(0.7)^{5-2} = 0.3087

P(X = 3) = C_{5,3}.(0.3)^{3}.(0.7)^{5-3} = 0.1323

P(X = 4) = C_{5,4}.(0.3)^{4}.(0.7)^{5-4} = 0.02835

P(X = 5) = C_{5,5}.(0.3)^{5}.(0.7)^{5-5} = 0.00243

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this question:

n = 5, p = 0.3, q = 1 - p = 0.7

So

P(X = x) = C_{5,x}.(0.3)^{x}.(0.7)^{5-x}

Possible values of x: 5 trials, so any value from 0 to 5.

For each value of x calculate p(☓ =x)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.3)^{0}.(0.7)^{5-0} = 0.16807

P(X = 1) = C_{5,1}.(0.3)^{1}.(0.7)^{5-1} = 0.36015

P(X = 2) = C_{5,2}.(0.3)^{2}.(0.7)^{5-2} = 0.3087

P(X = 3) = C_{5,3}.(0.3)^{3}.(0.7)^{5-3} = 0.1323

P(X = 4) = C_{5,4}.(0.3)^{4}.(0.7)^{5-4} = 0.02835

P(X = 5) = C_{5,5}.(0.3)^{5}.(0.7)^{5-5} = 0.00243

8 0
4 years ago
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