Question

At noon Joyce drove to the lake at 30 miles per hour. but she made the long walk back home at 4 miles per hour. How long did she walk if she was gone for 17 hours? How far did she walk?
PLEASE GIVE A REAL ANSWER , WILL GIVE BRANILIEST

Answer 1

Distance be x

• Time=Distance/Speef

So

• T_1=x/30
• T_2=x/4

ATQ

$\\ \tt\hookrightarrow T_1+T_2=17$

$\\ \tt\hookrightarrow x/30+x/4=17$

$\\ \tt\hookrightarrow 2x+15x/60=17$

$\\ \tt\hookrightarrow 17x=1020$

$\\ \tt\hookrightarrow x=60mi$

Answer 2

Answer:

60 miles

Step-by-step explanation:

let d = distance to the lake

Using:  time = distance ÷ speed

Create expressions for the time it takes for each journey:

Drive:  $t_1=\dfrac{d}{30}$

Walk:   $t_2=\dfrac{d}{4}$

If total time = 17 hours

$\implies t_1+t_2=17$

$\implies \dfrac{d}{30}+\dfrac{d}{4}=17$

$\implies \dfrac{17d}{60}=17$

$\implies 17d=1020$

$\implies d=\dfrac{1020}{17}$

$\implies d=60$

Therefore she walked 60 miles