Answer:
lleva 10 000 tornillos un contenedor
Step-by-step explanation:
Revenue, R = 130x
Profit, P = Revenue – Cost
P = R – C
P = 130x – 2950 + 6x + 0.1x^2
At P = 0
0 = -2950 + 136x +0.1x^2
X = 21.355, -1381.355
Therefore, manufacture greater than 21.355 items to make
profit.
Answer:
The answer is
x= -35
Step-by-step explanation:
x/5= -7
x= -35. :-)
Answer:
the minimum production level is costing $800 (0.8×$1000) per hour for 2000 (2×1000) items produced per hour.
Step-by-step explanation:
if there is no mistake in the problem description, I read the following function :
C(x) = y = 0.3x² - 1.2x + 2
I don't know if you learned this already, but to find the extreme values of a function you need to build the first derivative of the function y' and find its solutions for y'=0.
the first derivative of C(x) is
0.6x - 1.2 = y'
0.6x - 1.2 = 0
0.6x = 1.2
x = 2
C(2) = 0.3×2² - 1.2×2 + 2 = 0.3×4 - 2.4 + 2 = 1.2-2.4+2 = 0.8
so, the minimum production level is costing $800 (0.8×$1000) per hour for 2000 (2×1000) items produced per hour.
The average speed = (speed 1 + speed 2)/2
the average speed = (80/10 + 100/20)/2
the average speed = (8 + 5)/2
the average speed = 13/2
the average speed = 6.5 km/minute
