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3 years ago

Find the coordinates of the intersection of the diagonals

Mathematics

1 answer:

nalin [4]3 years ago

8 0

Answer:

We know the basic facts about parallelogram is The basic formula for calculating the area of a parallelogram is the length of one side times the height of the parallelogram to that side.

Step-by-step explanation:

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How do you solve this question

RUDIKE [14]

Answer:

64 is the correct answer

by isocles triangle therom and sum of triangle....

4 0

3 years ago

At the deli, 2 turkey subs and 5 veggie subs cost $29. 4 turkey subs and 3 veggie subs cost

MrMuchimi

Answer:

4/9 of sales are veggie 5/9 are turkey

4/(4+5)=4/9

5/(4+5)= 5/9

4/9 x 27 = 12

5/9 x 27 = 15

12 veggie subs sold and

15 turkey subs sold

12+15=27 total sold

Step-by-step explanation:

3 0

3 years ago

Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{8},0)(± 8 ,0)(, plus minus, square root o

Alchen [17]

Answer:

The equation of ellipse centered at the origin

$\frac{x^2}{18} +\frac{y^2}{10} =1$

Step-by-step explanation:

given the foci of ellipse (±√8,0) and c0-vertices are (0,±√10)

The foci are (-C,0) and (C ,0)

Given data (±√8,0)

the focus has x-coordinates so the focus is lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so c0-vertices are (0,±√10)

given focus C = ae = √8

Given co-vertices ( minor axis) (0,±b) = (0,±√10)

b= √10

The relation between the focus and semi major axes and semi minor axes are $c^2=a^2-b^2$

$a^{2} = c^{2} +b^{2}$

$a^{2} = (\sqrt{8} )^{2} +(\sqrt{10} )^{2}$

$a^{2} =18$

$a=\sqrt{18}$

The equation of ellipse formula

$\frac{x^2}{a^2} +\frac{y^2}{b^2} =1$

we know that $a=\sqrt{18} and b=\sqrt{10}$

Final answer:-

The equation of ellipse centered at the origin

$\frac{x^2}{18} +\frac{y^2}{10} =1$

8 0

3 years ago

Read 2 more answers

A cone with a height of 7in and a radius of 4in has what volume? (round to the nearest tenth)

-BARSIC- [3]

Would be 16.5 -> 16.6

5 0

3 years ago

Relations and functions need help please.

Ierofanga [76]

Just substitute the value of x back into the function.

So, $f(x) = -x^2 + 1$ becomes $f(-3) = -(-3)^2 + 1$

$f(-3) = 3^2 + 1 \\ \\ f(-3) = 9 + 1 \\ \\ f(-3) = 10$

So, f(-3) is equal to 10.

4 0

4 years ago