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Anna35 [415]
3 years ago
11

Two trains leave the station at the same time, one heading east and the other west. The eastbound train travels 10 miles per hou

r slower than the westbound train. If the two trains are 1000 miles apart after 5 hours, what is the rate of the eastbound train?
PLEASE QUICK ANSWER
Mathematics
1 answer:
Alex787 [66]3 years ago
6 0

Answer:

Eastbound train: 95 miles per hour

Westbound train: 105 miles per hour

Step-by-step explanation:

Let:

  • e = speed of the eastbound train
  • w = speed of the westbound train

The eastbound train travels 10 miles per hour slower than the westbound train

So e = w - 10

Every hour, the distance between the two trains is the sum of the values.

(w - 10) + w = distance apart in 1 hour

5(w - 10 + w) = distance after 5 hours

Solve:

  • 5(w - 10 + w) = 1000
  • 5(2w - 10) = 1000
  • 10w - 50 = 1000
  • 10w = 1050
  • w = 105

The westbound train is 105 miles/ hour.

The eastbound train is 95 miles per hour

-Chetan K

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Step-by-step explanation:

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3 years ago
Need some help please <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B11%7D%7B15%7D%20%20%2B%20%28%20-%20%20%5Cfrac%7B3%7D%7B
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-1/60

Step-by-step explanation:

\frac{11}{15}  + (- \frac{3}{4} )\\

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= \frac{44-45}{60}\\

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Jayden has 8 mints.his friend Michael has eight times as many mints as jayden.how many mints does michael have?
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Use appropriate algebra and theorem 7.2.1 to find the given inverse laplace transform. (write your answer as a function of t.) −
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4 years ago
Please help me get through this.
shtirl [24]

The value of x in the first question is 3/7.

The value of y in the second question is 17/22

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<em><u>The second question </u></em>

the first step is to simplify the terms in the numerator by combining similar terms

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