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AleksandrR [38]
3 years ago
7

PLEASE HELP PLEASE THANK U SO MUCH

Mathematics
1 answer:
arlik [135]3 years ago
4 0

Answer:

Step-by-step explanation:

x² - 7x - 18 = 0

Product = -18

Sum = -7

Factors = 2 , (-9)    {2*(-9) = -18  & 2 +(-9) = -7}

x²  + 2x - 9x - 18 = 0

x(x + 2) - 9(x + 2) = 0

(x +2)(x - 9)= 0

x + 2 = 0    ; x - 9 = 0

   x = -2     ; x  = 9

x = -2 , 9

Sale price = 272000

Reduction percentage = 15%

Let the original price = x

Reduction = 15% of x

Original price - reduction price = Sale price

x - 15% of x = £272000

x -\dfrac{15}{100}x = 272000\\\\\\\dfrac{100}{100}x-\dfrac{15}{100}x=272000\\\\\\\dfrac{85}{100}x=272000\\\\\\x=272000*\dfrac{100}{85}

x = 3200 * 100

Original price = £320000

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Find the value of the expression 3.28x –x2 for x =2.28
Sergio [31]

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3 years ago
Find the area of the trapezoidal cross-section of the irrigation canal shown below. Your answer will be in terms of h, w, and θ.
miskamm [114]

[w + (h/tan θ)] × h

<h3>Further explanation</h3>

We aim is to find the area of the trapezoidal cross-section of the irrigation canal.

The formula for the area of the trapezoid is \boxed{\boxed{ \ Area = \frac{1}{2} \times (a + b) \times h \ }}

  • a & b = parallel sides
  • h = height

We assume the lower side is \boxed{ \ a = w \ } and the upper side is b = x + w + x or \boxed{ \ b = w + 2x \ }. See the attached picture.

In the right triangles located on the left and right of the trapezoid, we calculate the value of x based on trigonometric ratios namely tan of theta.

\boxed{ \ tan \ \theta = \frac{opposite}{adjacent} \ }

\boxed{ \ tan \ \theta = \frac{h}{x} \ }

\boxed{ \ x = \frac{h}{tan \ \theta} \ }

Substitute the equation of x to \boxed{ \ b = w + 2x \ }.

We get \boxed{ \ b = w + \frac{2h}{tan \ \theta} \ }

Finally all components are complete and can be substituted into a formula to calculate the area of a trapezoid.

\circ \ \boxed{a = w}\\ \circ \ \boxed{ \ b = w + \frac{2h}{tan \ \theta} \ }\\\circ \ and \ h

\boxed{ \ Area = \frac{1}{2} \times (w + w + \frac{2h}{tan \ \theta}) \times h \ }

\boxed{ \ Area = \frac{1}{2} \times (2w + \frac{2h}{tan \ \theta}) \times h \ }

\boxed{ \ Area = \frac{1}{2} \times 2(w + \frac{h}{tan \ \theta}) \times h \ }

Hence, the area of the trapezoidal cross-section of the irrigation canal is \boxed{\boxed{ \ Area = (w + \frac{h}{tan \ \theta}) \times h \ }}

<h3>Learn more</h3>
  1. Find out the area of parallelogram brainly.com/question/4459688
  2. The order of rotational symmetry of rhombus  brainly.com/question/4228574
  3. Find out the coordinates of the image of a point after the triangle is rotated 270° about the origin brainly.com/question/7437053

Keywords: the trapezoidal, cross-section of the irrigation canal, the area, the answer will be in terms of h, w, and θ, trigonometric ratios, tan, opposite, adjacent, height, sides

3 0
4 years ago
Read 2 more answers
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