a recipe requires 1/3 cup of milk for each 1/4 cup of water how many cups of water are needed for each cup of milk

Mathematics

1 answer:

Darya [45]3 years ago

4 0

Answer:

1 cup of milk is used with 34 cup of water

Explanation:

A comparison between the cups of milk and cups of water can be written as a ratio:

Step-by-step explanation:

Note that: 1/3>1/4 milk : water 13:14 ←×12 to get rid of fractions

12/11×1/3:12/1×1/4= 4:3

4 cups of milk are used with 3 cups of water ←÷4

1 cup of milk is used with 34 cup of water

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Permutations of the word "Congratulations"

Mice21 [21]

Answer:

There are 15 letters, but if the two A's must always be together, that's the same as if they're just one letter, so our "base count" is 14! ; note that this way of counting means that we also don't need to worry about compensating for "double counting" identical permutations due to transposition of those A's, because we don't "count" both transpositions. However, that counting does "double count" equivalent permutations due to having two O's, two N's, and two T's, so we do need to compensate for that. Therefore the final answer is 14!/(23)=10,897,286,400

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2 years ago

The sum of two polynomials is –yz2 – 3z2 – 4y + 4. If one of the polynomials is y – 4yz2 – 3, what is the other polynomial? –2yz

marishachu [46]

The first polynomial is $y -4yz^2-3$ and let the second polynomial be P(y,z).

If the sum of two polynomials is $-yz^2-3z^2-4y+4$ , then $y-4yz^2-3+P(y,z)=-yz^2-3z^2-4y+4$ .

Take the first polynomial from the left side to the right side:

$P(y,z)=-yz^2-3z^2-4y+4 -(y-4yz^2-3),\\ P(y,z)=-yz^2-3z^2-4y+4 -y+4yz^2+3,\\ P(y,z)=3yz^2-3z^2-5y+7$ .

Answer: the second polynomial is $3yz^2-3z^2-5y+7$ .