Answer:
y+3=45(x+5)
Step-by-step explanation:
Hi there!
Point-Slope Form:
y-y1=m(x-x1)
Where
y1 stands for the y-coordinate of the point
m stands for the slope of the line
x1 stands for the x-coordinate of the point
In this case, the slope is 45, the y-coordinate of the given point is -3, and the x-coordinate of the point is -5.
Plug in the values and solve:
y-y1=m(x-x1)
y-(-3)=45(x-(-5)
y+3=45(x+5)
Hope it helps!
Enjoy your day!
Please feel free to ask if you have any doubts.
Check the picture below.
![~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{-9})\qquad B(\stackrel{x_2}{8}~,~\stackrel{y_2}{0}) ~\hfill AB=\sqrt{[ 8- 1]^2 + [ 0- (-9)]^2} \\\\\\ AB=\sqrt{7^2+(0+9)^2}\implies AB=\sqrt{7^2+9^2}\implies \boxed{AB=\sqrt{130}} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=~%5Chfill%20%5Cstackrel%7B%5Ctextit%7B%5Clarge%20distance%20between%202%20points%7D%7D%7Bd%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%7D~%5Chfill~%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20A%28%5Cstackrel%7Bx_1%7D%7B1%7D~%2C~%5Cstackrel%7By_1%7D%7B-9%7D%29%5Cqquad%20B%28%5Cstackrel%7Bx_2%7D%7B8%7D~%2C~%5Cstackrel%7By_2%7D%7B0%7D%29%20~%5Chfill%20AB%3D%5Csqrt%7B%5B%208-%201%5D%5E2%20%2B%20%5B%200-%20%28-9%29%5D%5E2%7D%20%5C%5C%5C%5C%5C%5C%20AB%3D%5Csqrt%7B7%5E2%2B%280%2B9%29%5E2%7D%5Cimplies%20AB%3D%5Csqrt%7B7%5E2%2B9%5E2%7D%5Cimplies%20%5Cboxed%7BAB%3D%5Csqrt%7B130%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![B(\stackrel{x_1}{8}~,~\stackrel{y_1}{0})\qquad C(\stackrel{x_2}{9}~,~\stackrel{y_2}{-8}) ~\hfill BC=\sqrt{[ 9- 8]^2 + [ -8- 0]^2} \\\\\\ BC=\sqrt{1^2+(-8)^2}\implies \boxed{BC=\sqrt{65}}](https://tex.z-dn.net/?f=B%28%5Cstackrel%7Bx_1%7D%7B8%7D~%2C~%5Cstackrel%7By_1%7D%7B0%7D%29%5Cqquad%20C%28%5Cstackrel%7Bx_2%7D%7B9%7D~%2C~%5Cstackrel%7By_2%7D%7B-8%7D%29%20~%5Chfill%20BC%3D%5Csqrt%7B%5B%209-%208%5D%5E2%20%2B%20%5B%20-8-%200%5D%5E2%7D%20%5C%5C%5C%5C%5C%5C%20BC%3D%5Csqrt%7B1%5E2%2B%28-8%29%5E2%7D%5Cimplies%20%5Cboxed%7BBC%3D%5Csqrt%7B65%7D%7D)
now, we could check for the CA distance, however, we already know that AB ≠ BC, so there's no need.
Since there is nothing on the left side of the equation besides the absolute value, you have to take 6m out of the absolute value and create 2 separate equations. These 2 equation will be 6m = 42 and 6m = -42.
You solve the equations normally:
6m = 42 6m = -42 (inverse to get m by itself, do on both sides)
/6 /6 /6 /6
m = 7 m = -7
The answer is a solution set:
[7, -7]
Answer:
13m/h
Step-by-step explanation:
1/5m=1/65h
65/5m=h
13m=h
13 miles per hour.
To find the area of a square with it's diagonal, there's actually a formula = (1/2)d², but here's how to do it if you don't have the formula:
The diagonal <em>c</em> separates the square into two of the same triangles. Therefore, we can apply Pythagorean Theorem
a²+b²=c² ← Since this is a square, a=b is a must
a²+a²=c² ← Combine like terms, and plug 26 in for c
2a²= 26² ← 26²=676, then divide 2 on both sides
a²= 676/2
a²=338 ← We can just stop here! Since <em>a </em>is a side of the square, therefore the area of a square = a²
Answer: 338 units²
