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3 years ago

3m^3 3 + 4f + 4 + 2f + 2f^2 2 + 1

Mathematics

1 answer:

damaskus [11]3 years ago

6 0

Answer:

33m^33+2f^22+6f+5

Step-by-step explanation:

this is the answer for if you are supposed to be simplifying :)

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A population of bacteria grows by a factor of 1.32 in one hour. What is the hourly growth rate?

pantera1 [17]

SInce the 'growth factor' is 1.32, the 'growth rate' is .32 or 32%

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3 years ago

last year, 639 students attended a summer camp. of those who attended this year, 0.5% also attended summer camp last year. about

lawyer [7]

Answer:

First of all, he have to find out what 0.5% of the students is.

Second of all, find out what 0.5 of 100 is. 100 divided by 0.5 is 200.

Third of all, divide 200 from 639. This equals 3.195

Since it is asking about how many, I would go with about 3. After all, you can't have have half of a person, so the decimals shouldn't be added.

Step-by-step explanation:

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3 years ago

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3 years ago

6 times the sum of d and 9

aksik [14]

Answer:

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Step-by-step explanation:

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3 years ago

In a binomial distribution, n = 8 and π=0.36. Find the probabilities of the following events. (Round your answers to 4 decimal p

skelet666 [1.2K]

Answer:

$\mathbf{P(X=5) =0.0888}$

P(x ≤ 5 ) = 0.9707

P ( x ≥ 6) = 0.0293

Step-by-step explanation:

The probability of a binomial mass distribution can be expressed with the formula:

$\mathtt{P(X=x) =(^{n}_{x} ) \ \pi^x \ (1-\pi)^{n-x}}$

$\mathtt{P(X=x) =(\dfrac{n!}{x!(n-x)!} ) \ \pi^x \ (1-\pi)^{n-x}}$

where;

n = 8 and π = 0.36

For x = 5

The probability $\mathtt{P(X=5) =(\dfrac{8!}{5!(8-5)!} ) \ 0.36^5 \ (1-0.36)^{8-5}}$

$\mathtt{P(X=5) =(\dfrac{8!}{5!(3)!} ) \ 0.36^5 \ (0.64)^{3}}$

$\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 \times 5!}{5!(3)!} ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 }{3 \times 2 \times 1} ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =({8 \times 7 } ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =0.0887645}$

$\mathbf{P(X=5) =0.0888}$ to 4 decimal places

b. x ≤ 5

The probability of P ( x ≤ 5) $\mathtt{P(x \leq 5) = P(x = 0)+ P(x = 1)+ P(x = 2)+ P(x = 3)+ P(x = 4)+ P(x = 5})$

${P(x \leq 5) = ( \dfrac{8!}{0!(8!)} \times (0.36)^0 \times (1-0.36)^8 \ ) + \dfrac{8!}{1!(7!)} \times (0.36)^1 \times (1-0.36)^7 \ +$ $\dfrac{8!}{2!(6!)} \times (0.36)^2 \times (1-0.36)^6 \ + \dfrac{8!}{3!(5!)} \times (0.36)^3 \times (1-0.36)^5 + \dfrac{8!}{4!(4!)} \times (0.36)^4 \times (1-0.36)^4 \ + \dfrac{8!}{5!(3!)} \times (0.36)^5 \times (1-0.36)^3 \ )$

P(x ≤ 5 ) = 0.0281+0.1267+0.2494+0.2805+0.1972+0.0888

P(x ≤ 5 ) = 0.9707

c. x ≥ 6

The probability of P ( x ≥ 6) = 1 - P( x ≤ 5 )

P ( x ≥ 6) = 1 - 0.9707

P ( x ≥ 6) = 0.0293

4 0

3 years ago

3m^3 ​3 ​​ + 4f + 4 + 2f + 2f^2 ​2 ​​ + 1

3m^3 3 + 4f + 4 + 2f + 2f^2 2 + 1