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Eddi Din [679]
2 years ago
14

There are 12 people at the movies. Child tickets are $5 and adult tickets are $10. How many children were there if they paid $60

?
Mathematics
1 answer:
o-na [289]2 years ago
8 0

Answer:

12 kids

Step-by-step explanation:

So if you keep adding 5 until you get to 60 that would get you to 12 children right? So there were 12 kids buying a ticket for $5 dollars that would mean the movie theater would get a total of $60 dollars from them!

Hope this helps,

Itz.Jordan  

Tiktok- dravenfact8

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Find the six trig function values of the angle 240*Show all work, do not use calculator
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Solution:

Given:

240^0

To get sin 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, sin 240 will be negative.

sin240^0=sin(180+60)

Using the trigonometric identity;

sin(x+y)=sinx\text{ }cosy+cosx\text{ }siny

Hence,

\begin{gathered} sin(180+60)=sin180cos60+cos180sin60 \\ sin180=0 \\ cos60=\frac{1}{2} \\ cos180=-1 \\ sin60=\frac{\sqrt{3}}{2} \\  \\ Thus, \\ sin180cos60+cos180sin60=0(\frac{1}{2})+(-1)(\frac{\sqrt{3}}{2}) \\ sin180cos60+cos180sin60=0-\frac{\sqrt{3}}{2} \\ sin180cos60+cos180sin60=-\frac{\sqrt{3}}{2} \\  \\ Hence, \\ sin240^0=-\frac{\sqrt{3}}{2} \end{gathered}

To get cos 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, cos 240 will be negative.

cos240^0=cos(180+60)

Using the trigonometric identity;

cos(x+y)=cosx\text{ }cosy-sinx\text{ }siny

Hence,

\begin{gathered} cos(180+60)=cos180cos60-sin180sin60 \\ sin180=0 \\ cos60=\frac{1}{2} \\ cos180=-1 \\ sin60=\frac{\sqrt{3}}{2} \\  \\ Thus, \\ cos180cos60-sin180sin60=-1(\frac{1}{2})-0(\frac{\sqrt{3}}{2}) \\ cos180cos60-sin180sin60=-\frac{1}{2}-0 \\ cos180cos60-sin180sin60=-\frac{1}{2} \\  \\ Hence, \\ cos240^0=-\frac{1}{2} \end{gathered}

To get tan 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, tan 240 will be positive.

tan240^0=tan(180+60)

Using the trigonometric identity;

tan(180+x)=tan\text{ }x

Hence,

\begin{gathered} tan(180+60)=tan60 \\ tan60=\sqrt{3} \\  \\ Hence, \\ tan240^0=\sqrt{3} \end{gathered}

To get cosec 240 degrees:

\begin{gathered} cosec\text{ }x=\frac{1}{sinx} \\ csc240=\frac{1}{sin240} \\ sin240=-\frac{\sqrt{3}}{2} \\  \\ Hence, \\ csc240=\frac{1}{\frac{-\sqrt{3}}{2}} \\ csc240=-\frac{2}{\sqrt{3}} \\  \\ Rationalizing\text{ the denominator;} \\ csc240=-\frac{2}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}} \\  \\ Thus, \\ csc240^0=-\frac{2\sqrt{3}}{3} \end{gathered}

To get sec 240 degrees:

\begin{gathered} sec\text{ }x=\frac{1}{cosx} \\ sec240=\frac{1}{cos240} \\ cos240=-\frac{1}{2} \\  \\ Hence, \\ sec240=\frac{1}{\frac{-1}{2}} \\ sec240=-2 \\  \\ Thus, \\ sec240^0=-2 \end{gathered}

To get cot 240 degrees:

\begin{gathered} cot\text{ }x=\frac{1}{tan\text{ }x} \\ cot240=\frac{1}{tan240} \\ tan240=\sqrt{3} \\  \\ Hence, \\ cot240=\frac{1}{\sqrt{3}} \\  \\ Rationalizing\text{ the denominator;} \\ cot240=\frac{1}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}} \\  \\ Thus, \\ cot240^0=\frac{\sqrt{3}}{3} \end{gathered}

5 0
1 year ago
Which data set is the farthest from a normal distribution?
Rudik [331]

Answer:

(C)0.9, 1.0, 1.0, 1.1, 1.1, 1.1, 1.2, 1.2, 1.3

Step-by-step explanation:

In (A), (B), (D) and (E) options, all have similar set of numbers and ranges between 2 to 10. Moreover these contains the whole numbers, so when we find mode, median and mean of these data sets, they will follow the same path.

But in (C), the data values involves decimals and are not the part of the other data values and it goes from 0.9-1.3, thus making them farthest from a normal distribution when mean, mode and median are calculated.

Thus, option (C) is correct.

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Step-by-step explanation:

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Triangle has sides that measure 33 cm, 65 cm, and 56 cm. Is it a right triangle? Explain
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Yes, by Pythagoras: Larguest side² = other side² + other side² (65²=33²+56²).






3 0
3 years ago
Question 3
BigorU [14]

Answer:

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Step-by-step explanation:

time = distance/speed

If x represents Jane's speed along the summit then her total exploration time is ...

  12/x + 40/(x -5) = 2 . . . . . hours

Multiplying by (x)(x -5), we get ...

  12(x -5) +40(x) = 2(x)(x -5)

Dividing by 2 and subtracting the left side gives ...

  x^2 -31x +30 = 0

  (x -30)(x -1) = 0 . . . . . factor

Solutions are x = 30 and x = 1, values of x that make the factors zero. A speed of 1 mph makes no sense in this problem, so ...

Jane's speed along the summit was 30 mph.

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3 years ago
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