Answer:

Step-by-step explanation:
In order to solve this problem, lets take the two terms in the binomial (4x and -3) and, for each one, multiply them by each term in the trinomial (2x^2, -7x, and 1):




Let's combine like terms to get our final answer:


The answers is A= C/-13
C= 13A
Okay, I think I understand this. Our first step is to solve how long the string is after he used some of it to tie the package. I have a feeling we have to subtract 7/8 - 1/5. Find a least common multiple (in this case, it's 40) and our new fractions are 35/40 and 8/45. Subtract:
35/40 - 8/40 = 27/40.
I don't think this can be simplified down any further as they do not have any common factors. So with that in mind, let's divide 27/40 with 5/1 (5/1 is basically 5 wholes but in fraction version)
When dividing fractions, you want to use the KCF technique (my old math teacher taught me this). Keep the first fraction the same (in this case, 27/40), change the sign from multiplication to division, and flip 5/1 to get it's reciprocal, 1/5. The equation will look like this:
27/40 * 1/5 = 27/200
So each piece is about 27/200 m in length (or 0.135 m in length).
If this is wrong, please let me know, but this is what I got out of this question. I hope this helped you :)
Given:
The measure of three sides of a triangle are 8, 7 and 14.
To find:
The measure of the angle opposite the side of length 8.
Solution:
According to the Law of Cosine:

Let a=8, b=7 and c=14, then by using Law of Cosine, we get



Taking cos inverse on both sides.



Therefore, the measure of the angle opposite the side of length 8 is 22.6 degrees.
MDC and largest number that can divide two numbers while
<span>340.728 2 </span>
<span>170.364 2 </span>
<span>85 182 </span>
<span>the highest numeropossivel that can divide two numbers are the same times 4 = 2.2</span>