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zimovet [89]
2 years ago
8

A kitten was given to a child as a birthday present when she was two years old. The cat lived a good life, but eventually became

old and passed away. If the sum of the ages totaled 30, how old was the cat when it died?
Mathematics
2 answers:
Charra [1.4K]2 years ago
5 0

Answer:

I would say 14

Step-by-step explanation:

Since the child was 2 years older from the start she would be 16 if the cat was 14. Adding them together makes it 30

Have an amazing day!

Please rate and mark brainliest!

:)

Katyanochek1 [597]2 years ago
4 0

Answer: 14 years

Step-by-step explanation:

Let the cat's age when it died = x.

Therefore, the child's age is 2 + x because he/she got the cat when he/she was 2 years old.

We can set up an equation.

x + (2+x) = 30

2x + 2 = 30

2x = 28

Therefore, x = 14

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myrzilka [38]
14(12)-200(3.2)
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faltersainse [42]

The price of one vegetarian special lunch is $7 and price of one chicken special lunch is $8.

Step-by-step explanation:

Let,

Price of one vegetarian special lunch = x

Price of one chicken special lunch = y

According to given statement;

21x+40y=467      Eqn 1

28x+36y=484     Eqn 2

Multiplying Eqn 1 by 28

28(21x+40y=467)\\588x+1120y=13076\ \ \ Eqn\ 3

Multiplying Eqn 2 by 21

21(28x+36y=484)\\588x+756y=10164\ \ \ Eqn\ 4

Subtracting Eqn 4 from Eqn 3

(588x+1120y)-(588x+756y)=13076-10164\\588x+1120y-588x-756y=2912\\364y=2912

Dividing both sides by 364

\frac{364y}{364}=\frac{2912}{364}\\y=8

Putting y=8 in Eqn 1

21x+40(8)=467\\21x+320=467\\21x=467-320\\21x=147

Dividing both sides by 21

\frac{21x}{21}=\frac{147}{21}\\x=7

The price of one vegetarian special lunch is $7 and price of one chicken special lunch is $8.

Keywords: linear equation, elimination method

Learn more about elimination method at:

  • brainly.com/question/10081622
  • brainly.com/question/10341324

#LearnwithBrainly

5 0
3 years ago
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Answer:

  a. 1.2 ohms

  b. 6 ohms

Step-by-step explanation:

As with any problem involving evaluation of a formula, substitute the given values for the corresponding variables and do the arithmetic.

a.

  R=\dfrac{1}{\dfrac{1}{R_1}+\dfrac{1}{R_2}}=\dfrac{1}{\dfrac{1}{2}+\dfrac{1}{3}}=\dfrac{1}{\left(\dfrac{5}{6}\right)}=\boxed{\dfrac{6}{5}=1.2}

__

b.

  R=\dfrac{1}{\dfrac{1}{R_1}+\dfrac{1}{R_2}}=\dfrac{1}{\dfrac{1}{10}+\dfrac{1}{15}}=\dfrac{1}{\left(\dfrac{5}{30}\right)}=\dfrac{30}{5}=\boxed{6}

_____

<em>Comment on these problems</em>

You will notice that the values in part (b) are 5 times those in part (a). So, it is no surprise that the answer in part (b) is 5 times the answer in part (a).

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In triangle XYZ, shown above, what is the value of cos(X)?
adell [148]

Answer:

A

Step-by-step explanation:

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I got -55,180. To get that answer you need to subtract them. I hope this helps!!!
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