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zimovet [89]
2 years ago
8

A kitten was given to a child as a birthday present when she was two years old. The cat lived a good life, but eventually became

old and passed away. If the sum of the ages totaled 30, how old was the cat when it died?
Mathematics
2 answers:
Charra [1.4K]2 years ago
5 0

Answer:

I would say 14

Step-by-step explanation:

Since the child was 2 years older from the start she would be 16 if the cat was 14. Adding them together makes it 30

Have an amazing day!

Please rate and mark brainliest!

:)

Katyanochek1 [597]2 years ago
4 0

Answer: 14 years

Step-by-step explanation:

Let the cat's age when it died = x.

Therefore, the child's age is 2 + x because he/she got the cat when he/she was 2 years old.

We can set up an equation.

x + (2+x) = 30

2x + 2 = 30

2x = 28

Therefore, x = 14

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MatroZZZ [7]

The common denominator for 25 and 20 would be 100

25 x 4 = 100

20 x 5 = 100

Rewrite 14/25 as 14 x 4 / 25 x 4 = 56/100

Rewrite 11/20 as 11 x 5 / 20 x 5 = 55/100

14/25 is greater than 11/20

14/25 > 11/20

3 0
3 years ago
Please help me answer this step by step would be helpful
UNO [17]

Answer:

Step-by-step explanation:

The viniculum in a fraction represents subtraction with exponents.

Subtracting exponents gives us  3^12/3^8 * 3^2

Simplifying gives 3^12/3^10. Then, we can achieve 3^12 - 3^10.

This equals 3^2.

3^2 = 9.

So 9 is the answer of your question.

6 0
3 years ago
Can someone check if this is the correct answer? Since you can't sell part of a basket.
soldier1979 [14.2K]
Yes it’s the good you’re really a good student
4 0
3 years ago
Find the missing side of each triangle. Leave your answers in simplest radical form.
rosijanka [135]

Answer:

Step-by-step explanation:

pythagoras theorem

a^2+b^2=c^2

8^2+9^2=x^2

64+81=x^2

145=x^2

\sqrt{145=x

4 0
3 years ago
Read 2 more answers
Solve the equation for exact solutions over the interval​ [0, 2π​).
quester [9]

Answer:

\displaystyle x=\left\{0, \frac{2\pi}{3}, \frac{4\pi}{3}\right\}

Step-by-step explanation:

We want to solve the equation:

-2\cos^2(x)=-\cos(x)-1

Over the interval [0, 2π).

First, notice that this is in quadratic form. So, to make things simpler, we can let <em>u</em> = cos(x). Substitute:

-2u^2=-u-1

Rearrange:

2u^2-u-1=0

Factor:

(2u+1)(u-1)=0

Zero Product Property:

2u+1=0\text{ or } u-1=0

Solve for each case:

\displaystyle u=-\frac{1}{2}\text{ or } u=1

Back-substitute:

\displaystyle \cos(x)=-\frac{1}{2}\text{ or } \cos(x)=1

Using the unit circle:

\displaystyle x=\left\{0, \frac{2\pi}{3}, \frac{4\pi}{3}\right\}

7 0
3 years ago
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