Lets just choose the first one, 3 4 and 5. According to the Pythagorean Theorem,
a^2+b^2=c^2
So lets plug in our numbers.
3^2+4^2=c^2
The answer should be 5, but lets make sure.
3*3 = 9
4*4 = 16
9+16=c^2
25 = c^2
Square root both sides so:
5=c
And sure enough 5 is the last number on that list. The order doesn’t matter as long as the value you are trying to find is the c^2.
Answer:
$14
Step-by-step explanation:
The necklaces cost $8, so two would be $8+$8=$16
Now do the original $30 minus the $16 dollars spent
You now have $14 left.
Answer:
A. 4
B. y = x + 4
Step-by-step explanation:
Mode is the most.
What number appears the most? 8. 8 appears twice.
Mean is the average.
Add up all the numbers. 5+8+16+14+2+18+8=71
Then divide by how many numbers there are. 71/7=10.1
Median is alway in-between.
If you set up a number line in order of least to greatest, what number is in the middle?
2,5,8,8,14,16,18
we can erase the numbers on each end to find the middle.
2,5,8,8,14,16,18
5,8,8,14,16
8,8,14,16
8,14
Uh oh! There are two numbers in the middle. In this case you find the average of these two numbers.
8+14= 22
22/2=11
The range is the highest number in your set of data minus the lowest number in your set of data.
So, 18-2=16
In conclusion...
Mode:8
Mean:10.1
Median:11
Range:16