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3 years ago

Question 2 (1 point) (06.04 MC) Find the product of (x − 5)2. Question 2 options: x2 + 10x + 25 x2 − 10x + 25 x2 − 25 x2 + 25

Mathematics

1 answer:

vladimir1956 [14]3 years ago

4 0

${ (x - 5) }^{2} = {x}^{2} - 10x + 25$

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In the diagram AB bisects FAE. BF=5x and BE=x2+6. Solve for x.

Lilit [14]

$If\ AB^{\to}\ bisects\ \angle FAE\ then\ m\angle BAF=m\angle BAE\\\\5x=x^2+6\\\\x^2-5x+6=0\\\\x^2-2x-3x+6=0\\\\x(x-2)-3(x-2)=0\\\\(x-2)(x-3)=0\iff x-2=0\ or\ x-3=0\\\\\boxed{x=2\ or\ x=3}$

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3 years ago

A 10-foot ladder leans against a wall so that it is 6 feet high at the top. The ladder is moved so that the base of the ladder t

konstantin123 [22]

Answer:

The top of the ladder is now at 10 ft.

Step-by-step explanation:

At the start, we have a height H=6, a length L=10 and a base B, that has to be calculated by the Pythagorean theorem:

$B^2=L^2-H^2=10^2-6^2=100-36=64\\\\B=\sqrt{64}=8$

The base is moved twice the distance the height moves up.

We called this distance x, so we have:

$L^2=(H+x)^2+(B-2x)^2=H^2+2Hx+x^2+B^2-4Bx+4x^2\\\\L^2=(H^2+B^2)+5x^2+(2H-4B)x\\\\L^2=L^2+5x^2+(2H-4B)x\\\\0=5x^2+(2H-4B)x\\\\5x+(2H-4B)=0\\\\x=\dfrac{4B-2H}{5}=\dfrac{4*8-2*6}{5}=\dfrac{32-12}{5}=\dfrac{20}{5}=4$

The new height (H+x) is

$H'=H+x=6+4=10$

The base travels 2x=8, so the new base B' is 0.

This means that the ladder is all against the wall (L=H').

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3 years ago

suppose that f(x)=x^2 and g(x)=2/5 x^2. which statement best compares the graph of g(x) with the graph of f(x)

Andrews [41]

Answer:

does it have a picture

Step-by-step explanation:

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3 years ago

-2(x+3)= what's the answer

yuradex [85]

-2(x + 3)
Distribute the -2 to both x and +3 since the -2 is outside of the parentheses
-2 * x = -2x
-2 * 3 = -6
Therefore, your answer is -2x - 6

6 0

3 years ago

Read 2 more answers

A line contains the points (1, –6) and (–2, 6). What is the slope of a line that is perpendicular to this line?

OlgaM077 [116]

First, find the slope of the line contains the points (1,-6) and (-2,6) using slope formula
m = $\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

plug in the numbers
m = $\dfrac{6-(-6)}{-2-1}$
m = $\dfrac{6+6}{-3}$
m = $\dfrac{12}{-3}$
m = -4

Second, determine the slope of perpendicular line
The slope of the perpendicular line is the opposite and reciprocal from the other line. Thus, the slope is $\dfrac{1}{4}$

3 0

3 years ago