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2 years ago

6

Ollie, a young man with insurance coverage, ends up in the hospital with a broken wrist suffered while playing football with a g

roup of friends. After an X-ray, MRI, doctor visit, orthopedist visit, and cast, he leaves the hospital with a bill for $9,000. He has a $2,000 annual deductible, and this is his first visit to a doctor in this calendar year. He also has a 20% co-pay. The amount that he is responsible for paying is?
Answer choices ↓

nothing since he did not need to stay overnight in the hospital.

$3,400.

only the $2,000 annual deductible.

$1,800.

1 answer:

Ipatiy [6.2K]2 years ago

6 0

Answer: only the $2,000 annual deductible.

$1,800.

Step-by-step explanation:

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Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago

Help help help help

Alex

Answer:

<h3>b= $\frac{t-5}{4}$ </h3>

Step-by-step explanation:

4b+5=t

First, you must get the variable alone! Substract 5 from both sides!

4b<u>+5=t </u>

-5 -5

The 5 cancels out because 5-5=0

The new equation is 4b=t-5

You must divide by 4 to get the variable alone since your solving for b!

<u>4b=t-5</u>

4 4

b= $\frac{t-5}{4} \\$

This is your answer!

5 0

2 years ago

Suppose you removed the zero from each decimal below. Which decimal's value would be changed?

expeople1 [14]

Answer:

c

Step-by-step explanation: if you remove the 0 then you get 3.27

3 0

2 years ago

As part of a science experiment, Giovanni measured the distance a caterpillar traveled over different time intervals. In the fir

777dan777 [17]

Step-by-step explanation:

its b

8 0

3 years ago

At noon, Bradley began steadily increasing the

barxatty [35]

Answer:

25.5 mph

Step-by-step explanation:

So Bradley's speed can be modeled by the equation y=2x+40 where y=speed, x=time in hours after noon, and b=initial speed

So 12:15 is 15 minutes after noon, which is also 0.25 or 1/4 of an hour after noon. This is the x-value. Plug this into the equation to get his speed at 12:15

y=2(0.25)+40

y=0.5+40

y=40.5

So his speed was 40.5 at the time and since he was going 15 miles over the speed limit, the speed limit is 15 less than his speed

40.5 - 15 = 25.5

8 0

1 year ago

Read 2 more answers