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LuckyWell [14K]
3 years ago
11

2. Select each number that could be multiplied by 2,789 to get a number greater than 2.789.

Mathematics
2 answers:
horrorfan [7]3 years ago
8 0

Answer:

the answer is 11/3

Step-by-step explanation:

sertanlavr [38]3 years ago
6 0

Answer:

the answer is 11/3

Step-by-step explanation:

I took the quiz

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A certain computer loses half of its value every two years. If the value of the computer after 3 years is 425, what was the init
IrinaVladis [17]

Answer:

1,700      

Step-by-step explanation:

The computation of the initial value of the computer is shown below:

Let us assume the value of a certain computer in the first year is X

In the second year, it is \frac{X}{2}

In the third year, it is \frac{X}{2}

In the fourth year, it is \frac{X}{4}

Now it is given that after 3 years, the value of the computer is = 425 i.e equal to

\frac{X}{4} = 425

So, X = 1,700

Hence, the initial value of the computer is 1,700      

6 0
4 years ago
What is the factored form of the function f(x)=x^3+8x^2+5x−50?
Inga [223]

Answer:

the factors of  f(x)=x^3+8x^2+5x-50 are (x-2)(x+5)(x+5)

Step-by-step explanation:

We need to factorise the function f(x)=x^3+8x^2+5x-50

If a number is a factor of this function than it must be completely divisible by last co-efficient. Our last co-efficient is -50

Checking few numbers:

f(1)=(1)^{3}+8(1)^2+5(1)-50\\f(1)=1+8+5-50\\f(1)=-32\\Now \ putting \ x= 2 \\f(2)=(2)^{3}+8(2)^2+5(2)-50\\f(2)=8+8(4)+10-50\\f(2)=8+32+10-50\\f(2)=0

So, f(2)=0 which means x-2 is a factor of the given function. Now we will perform long division of x^3+8x^2+5x-50 by (x-2) to find other factors

The long division is shown in figure attached.

After long division we get: x^2+10x+25

The equation x^2+10x+25 can be further simplified as: (x+5)(x+5) or (x+5)^2

So, the factors of  f(x)=x^3+8x^2+5x-50 are (x-2)(x+5)(x+5)

3 0
4 years ago
Simplifying Nonperfect Roots
Bond [772]
Short Answer:Choice C [Third one down]
Remark

Start with the number so I can talk about the basic principle at work. The way to work it is to factor 162 into prime factors and hope there are at least 3 that are the same. 
162 = 2 * 81
162 = 2 * 3 * 3 * 3 * 3

Now When you take the cube root of that, you get \sqrt[3]{2*2*2*2*3}
Here's the rule for a cube root. For every 3 prime factors under the cuberoot sign, you take out one and throw the other two away. So for cube root of 81,
you would factor it as ∛(81) = ∛(3 * 3 * 3 * 3) = 3∛3.

So out of four 3s under the cube root sign,  you have 1 outside the root sign and one inside the root sign. 2 of the four 3s have been thrown away.

Continuation.
X first
You want 2 xs outside the root sign
∛(x * x * x * x * x *x ) = (x * x)  You have thrown away 2 xs for every x outside the cube root sign
C = 6 There are no left overs.

Y second
For the ys, you need 1 outside and 2 inside the root sign. that's because you need 5 altogether.
∛(y * y * y * y * y) = y ∛y^2

Answer 
c = 6; d = 2
Choice C <<<<<< answer 
3 0
3 years ago
(−7x 2 −4)+(−7x 2 −6x−2)
seropon [69]

-20

Explanation:

( − 7   ^ 2  −  4 )  +  ( − 7   ^ 2  −  6  − 2 )

Eliminate the redundant parentheses, subtract the numbers which will get you, combine like terms, rearrange terms, then your solution is:

− 1 4 2 −6 −6

Figure that problem out then you will get -20.

8 0
3 years ago
Read 2 more answers
3–4+10+2q simplified
nlexa [21]
The answer is negative 3
4 0
4 years ago
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