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Colt1911 [192]
2 years ago
14

Factor the difference of two perfect squares using the X method. An x-method chart shows the product a c at the top of x and b a

t the bottom of x. What are the two binomial factors for x2 – 25? (x – 5)(x – 5) (x 5)(x 5) (x – 20)(x 5) (x – 5)(x 5).
Mathematics
1 answer:
elena-14-01-66 [18.8K]2 years ago
6 0

By using x-method we got that factorization x^2-25  is (x+5)(x-5)

<h3>What is factorization ?</h3>

factorization is writing a expression as a product of several factors.

So Given polynomial is

x^2-25

Now we will factorise  this using x method

Here a=1     b=0 and c= -25

so ac=-25

Now We will write -25 at the top.

and 0 at the bottom.

No we will find two numbers that multiply to the top number -25 and add to the bottom number 0. Hence those numbers are -5 and 5.

Now we can write equation as

x^2-5x+5x-25\\\\x(x-5)+5(x-5)\\\\(x+5)(x-5)

By using x-method we got that factorization x^2-25  is (x+5)(x-5)

To learn more about factorization  visit : brainly.com/question/11579257

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Please please need help on these two
kati45 [8]

Answer:

( f + g ) (x) = 2 x^{2}  + x - 4

g(x) - f(x) = x^{2}  - 2 x - 4

Step-by-step explanation:

  1. f(x) = 4 x - 4 and g(x) = 2 x^{2} - 3 x

( f + g ) (x) = f(x) + g(x)

                = 4 x - 4 + 2  x^{2}  - 2 x

                = 2 x^{2} + x -4

   2.  g(x) = x^{2}  + 1 and f(x) = 2 x + 5

g(x) - f(x) = x^{2}  + 1 - (2 x + 5)

              = x^{2}  + 1 - 2 x - 5

              = x^{2}  - 2 x - 4

6 0
3 years ago
What is the sin, cos, and tan of -495 degrees, and -20π/3  ??
Diano4ka-milaya [45]
Sin-495 = 0.98
cos-495 = 0.19
tan-495 = 4.95

sin<span>-20π/3</span> = 0
cos<span>-20π/3</span> = 0.3
tan<span>-20<span>π/3</span></span> = 0





7 0
3 years ago
A college student organization wants to start a nightclub for students under the age of 21. To assess support for this proposal,
eduard

Answer:

a) Sample size = 822

b) Margin of error = 0.03407          

Step-by-step explanation:

We are given the following in the question:

p = 74% = 0.74

a) Sample size is required to obtain margin of error of 0.03

Formula:

\text{Margin of error} = z_{\text{statistic}}\times \sqrt{\dfrac{p(1-p)}{n}}}

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

Putting values, we get,

0.03 = 1.96\times \sqrt{\dfrac{0.74(1-0.74)}{n}}\\\\n = (\dfrac{1.96}{0.03})^2(0.74)(1-0.74)\\\\n = 821.24 \approx 822

Thus, the sample size must be approximately 822  to obtain a 95% confidence interval with an approximate margin of error of 0.03

b) Margin of error for the 95% confidence interval

p = 54% = 0.54

Formula:

\text{Margin of error} = z_{\text{statistic}}\times \sqrt{\dfrac{p(1-p)}{n}}}

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

Putting values, we get,

\text{Margin of error} = 1.96\times \sqrt{\dfrac{0.54(1-0.54)}{822}}\\\\=0.03407

The margin of error now will be 0.03407.

5 0
4 years ago
A bag contains eleven equally sized marbles, which are numbered. Two marbles are chosen at random and replaced after each select
Digiron [165]

Answer:

B. \frac{24}{121}.

Step-by-step explanation:

Total number of marbles = 11.

Since, after choosing the first marble, we are putting it back and then the second marble is chosen.

As, there are 4 shaded marbles.

So, the probability of getting the first marble shaded = \frac{\binom{4}{1}}{\binom{11}{1}} = \frac{4}{11}

Also, there are 6 odd labeled marbles.

So, the probability of getting the second marble being odd labeled = \frac{\binom{6}{1}}{\binom{11}{1}} = \frac{6}{11}

So, the probability of getting the first marble shaded and second marble labeled odd = \frac{4}{11}\times \frac{6}{11} = \frac{24}{121}.

Hence, the required probability is \frac{24}{121}.

4 0
3 years ago
Read 2 more answers
NEED ASAP 100 POINTS!!!!!!!!!
Charra [1.4K]

Answer:

3) a. f(-4) = 2

   b. f(0) = 0

   c. f(3) = -1.5

   d. f(-5) = 0

   e. x = -4

    f. x= 0

4) a. f(-1) = 1

   b. f(3) = -1

   c. 1

   d. -5

5) f(6) = 2

   f(2) = 4

   f(0) = 7

   f(5) = 1.5

    x=4

7 0
3 years ago
Read 2 more answers
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