Question

A bag contains eleven equally sized marbles, which are numbered. Two marbles are chosen at random and replaced after each selection.
What is the probability that the first marble chosen is shaded and the second marble chosen is labeled with an odd number?

it is letter b

Answer 1

Answer:

B.

Step-by-step explanation:

on edge

Answer 2

Answer:

B. $\frac{24}{121}$.

Step-by-step explanation:

Total number of marbles = 11.

Since, after choosing the first marble, we are putting it back and then the second marble is chosen.

As, there are 4 shaded marbles.

So, the probability of getting the first marble shaded = $\frac{\binom{4}{1}}{\binom{11}{1}}$ = $\frac{4}{11}$

Also, there are 6 odd labeled marbles.

So, the probability of getting the second marble being odd labeled = $\frac{\binom{6}{1}}{\binom{11}{1}}$ = $\frac{6}{11}$

So, the probability of getting the first marble shaded and second marble labeled odd = $\frac{4}{11}\times \frac{6}{11}$ = $\frac{24}{121}$.

Hence, the required probability is $\frac{24}{121}$.