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gavmur [86]
3 years ago
9

PLEASE HELP ME RN!!!!!

Mathematics
1 answer:
Serhud [2]3 years ago
5 0

Answer:

32,  2√7

Explanation:

given: \sf \bold x^2+6x+2=0

using quadratic formula:   \boxed{\boxed{\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a}}}

solve using the equation:

  • \sf x_{1,\:2}=\dfrac{-6\pm \sqrt{6^2-4\cdot \:1\cdot \:2}}{2\cdot \:1}

  • \sf x_1=\dfrac{-6+2\sqrt{7}}{2\cdot \:1},\:x_2=\dfrac{-6-2\sqrt{7}}{2\cdot \:1}

  • \sf x=-3+\sqrt{7},\:x=-3-\sqrt{7}

given a > β

  • so -3+√7 > -3-√7
  • a =  -3+√7 and β = -3-√7

solve:

  • (-3+√7)² + ( -3-√7)²
  • 32

and

  • -3+√7  - -3-√7
  • 2√7
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Nicole took a taxi from her house to the airport. The taxi company charged a pick-up fee of $2.90 plus $1.75 per mile. The total
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Answer:

  24 miles

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The total fare is the sum of the pickup fee and the mileage charge. For xx miles, the mileage charge will be 1.75xx, so the total is ...

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3 years ago
Find the vertices and foci of the hyperbola with equation quantity x plus one squared divided by sixteen minus the quantity of y
katrin2010 [14]

Answer:

The vertices are (3 , -5) , (-5 , -5)

The foci are (4 , -5) , (-6 , -5)

Step-by-step explanation:

* Lets study the equation of the hyperbola

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  center (h , k) and transverse axis parallel to the x-axis is

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* Now lets solve the problem

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* From the equation

# a² = 16 ⇒ a = ± 4

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# h = -1

# k = -5

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∴ The foci are (-1 + 5 , -5) , (-1 - 5 , -5)

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4 0
4 years ago
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3 years ago
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