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3 years ago

Plsss help!! In triangle ABC, AC=13, BC=84, and AB=85. Find the measure of angle C

Mathematics

1 answer:

Ivahew [28]3 years ago

5 0

Answer:

90°

Those three sides make a right triangle,

√(84²+13²) = 85

So angle C is 90°

Answered by GAUTHMATH

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mylen [45]

30 ounces

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Johnny needs to save $24.00 to buy a new video game. Three weeks after saving, he has $6.00. After 6 weeks, he has $12.00. If Jo

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Find the domain of the function algebraically:<br><br> <img src="https://tex.z-dn.net/?f=R%28x%29%3D%5Cfrac%7Bx%7D%7Bx%5E%7B2%7D

BigorU [14]

The domain of the function is all real numbers except 2 and -1

Step-by-step explanation:

Domain is the set of inputs of a function on which the function is defined.

Given function is:

$R(x) = \frac{x}{x^2-x-2}$

In case of a function involving fraction, the function is undefined if the denominator is zero so in order to find the domain of the function algebraically , we have to find the values on which the function will be undefined

$x^2-x-2 = 0\\x^2-2x+x-2 = 0\\x(x-2)+1(x-2) = 0\\(x+1)(x-2) = 0\\x+1 = 0 => x=-1\\x-2=0 = > x=2$

The function will be undefined on x=-1 and x=2

So,

The domain of the function is all real numbers except 2 and -1

Keywords: Domain, functions

Learn more about domain and functions at:

#LearnwithBrainly

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3 years ago

0612103993 please answer <br><br> 529185/(x/y-2)=3. solve for x and y

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3 years ago

A homeowner plans to enclose a 200 square foot rectangular playground in his garden, with one side along the boundary of his pro

Anestetic [448]

Answer:

Therefore the length and width of the playground are 15.5 feet and 12.9 feet respectively.

Step-by-step explanation:

Given that, a homeowner plans to enclose a 200 square foot rectangle playground.

Let the width of the playground be y and the length of the playground be x which is the side along the boundary.

The perimeter of the playground is = 2(length +width)

=2(x+y) foot

The material costs $1 per foot.

Therefore total cost to give boundary of the play ground

=$[ 2(x+y)×1]

=$[2(x+y)]

But the neighbor will play one third of the side x foot.

So the neighbor will play $=\$(\frac13x)$

Now homeowner's total cost for the material is

$=\$[ 2(x+y)-\frac13x]$

$=\$[2x+2y-\frac13x]$

$=\$[2y+x+x-\frac13x]$

$=\$[2y+x+\frac{3x-x}{3}]$

$=\$[2y+x+\frac{2}{3}x]$

$=\$[2y+\frac53x]$

$\therefore C(x)=2y+\frac53x$

where C(x) is total cost of material in $.

Given that the area of the playground is 200.

We know that,

The area of a rectangle is =length×width

=xy square foot

∴xy=200

$\Rightarrow y=\frac{200}{x}$

Putting the value of y in C(x)

$\therefore C(x)=2(\frac{200}{x})+\frac53x$

The domain of C is $(0,\infty )$ .

$\therefore C(x)=2(\frac{200}{x})+\frac53x$

Differentiating with respect to x

$C'(x)= - \frac{400}{x^2}+\frac53$

Again differentiating with respect to x

$C''(x) = \frac{800}{x^3}$

To find the critical point set C'(x)=0

$\therefore 0= - \frac{400}{x^2}+\frac53$

$\Rightarrow \frac{400}{x^2}=\frac{5}{3}$

$\Rightarrow x^2 =\frac{400\times 3}{5}$

$\Rightarrow x=\sqrt{240}$

$\Rightarrow x=15.49 \approx15.5$

Therefore

$\left C''(x) \right|_{x=15.5}=\frac{800}{15.5^3}>0$

Therefore at x= 15.5 , C(x) is minimum.

Putting the value of x in $y=\frac{200}{x}$ we get

$\therefore y=\frac{200}{15.5}$

=12.9

Therefore the length and width of the playground are 15.5 feet and 12.9 feet respectively.

6 0

3 years ago