2 years ago

Plsss help!! In triangle ABC, AC=13, BC=84, and AB=85. Find the measure of angle C

Mathematics

1 answer:

Ivahew [28]2 years ago

5 0

Answer:

90°

Those three sides make a right triangle,

√(84²+13²) = 85

So angle C is 90°

Answered by GAUTHMATH

You might be interested in

A company makes wax candles in the shape of a cylinder. Each candle has a diameter of 8 inches and a height of 3 inches. How muc

Sveta_85 [38]

Answer:

18,086.4 cubic units

Step-by-step explanation:

The volume of one such cylinder can be computed by multiplying the height by pi by the radius squared: 3×3.14×4²=150.72.

If you want to make 120 candles, multiply that number by 120: 150.72×120=18086.4.

3 0

2 years ago

The equation y=1/2x represents a proportional relationship. What is the constant of proportionality ? I NEED HELP ASAP

hram777 [196]

Answer:

yx14

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

X^4 -(3m+2)x^2 +3m+1 +0 <br> tìm m để phương trình có 4 nghiệm phân biệt nhỏ hơn 2

Kobotan [32]

Answer:

4848

Step-by-step explanation:

hope I helped

8 0

2 years ago

What is the difference? startfraction 2 x 5 over x squared minus 3 x endfraction minus startfraction 3 x 5 over x cubed minus 9

weeeeeb [17]

The difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

<h3>How to determine the difference?</h3>

The expression is given as:

$\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$

Factor the denominators of the expressions:

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}$

Apply the difference of two squares to x² - 9

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x - 3)(x + 3)}$

Take LCM

$\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

Hence, the difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$