Answer:
Option C is correct.
Step-by-step explanation:
<h2>
I am really stuck on this question help me please
1 answer:
You might be interested in
In the first octant, the given plane forms a triangle with vertices corresponding to the plane's intercepts along each axis.
Now that we know the vertices of the surface
, we can parameterize it by
where
and 
. The surface element is
With respect to our parameterization, we have
, so the surface integral is
Now that we know the vertices of the surface
where
With respect to our parameterization, we have
Answer:
90°
Step-by-step explanation:
Through point O draw a ray on left side of O which is || to AB & CD and take any point P on it.
Therefore,
∠ABO + ∠BOP = 180° (by interior angle Postulate)
118° + ∠BOP = 180°
∠BOP = 180° - 118°
∠BOP = 62°.... (1)
Since, ∠BOP + ∠POD = ∠BOD
Therefore, 62° + ∠POD = 152°
∠POD = 152° - 62°
∠POD = 90°.....(2)
∠POD + ∠ODC = 180° (by interior angle Postulate)
90° + ∠ODC = 180°
∠ODC = 180° - 90°