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Paha777 [63]
3 years ago
8

Using tje logarithm find the square of 86.46​

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
4 0
If i am correct, the square of 86.46 is 9.2983869568867
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A coin is flipped twice. What is the probability that it will come up once heads and once tails
Illusion [34]

1/2 or 50%, because there are two possibilities out of four.

If you think about flipping a coin twice, there are exactly four possible outcomes:

  Flip 1          Flip 2

1. tails            heads

2. tails            tails

3. heads        tails

4. heads        heads

In two of these possibilities (1 and 3) the coin flipped different sides.

That means 2/4 possibilities matched, and this can be reduced to 1/2

5 0
3 years ago
twelve pounds of beans are being evenly distributed into eight bags how many pounds of beans are there answer must be in simples
vaieri [72.5K]
Youll have 1.5 pounds of beans in each bag. 

12 divided by 8 = 1.5 
5 0
4 years ago
Read 2 more answers
Answer please i need help
Sedbober [7]
Which democratic ideal is part of the Declaration of Independence?

separation of powers

freedom of speech, religion, and the press

the right to life, liberty, and the pursuit of happiness

universal voting rights
7 0
2 years ago
Read 2 more answers
A researcher is concerned about the impact of students working while they are enrolled in classes, and she likes to know if stud
8_murik_8 [283]

Answer:

(a) Point estimate = 7.10

(b) The critical value is 1.960

(c) Margin of error = 0.800

(d) Confidence Interval = (6.3, 7.9)

(e) We are 90% confident that the average number of hours worked by the students is between 6.3 and 7.9

Step-by-step explanation:

Given

\bar x = 7.10 -- sample mean

\sigma=5 --- sample standard deviation

n = 150 --- samples

Solving (a): The point estimate

The sample mean can be used as the point estimate.

Hence, the point estimate is 7.10

Solving (b): The critical value

We have:

CI = 90\% --- the confidence interval

Calculate the \alpha level

\alpha = 1 - CI

\alpha = 1 - 90\%

\alpha = 1 - 0.90

\alpha = 0.10

Divide by 2

\frac{\alpha}{2} = 0.10/2

\frac{\alpha}{2} = 0.05

Subtract from 1

1 - \frac{\alpha}{2} = 1 - 0.05

1 - \frac{\alpha}{2} = 0.95

From the z table. the critical value for 1 - \frac{\alpha}{2} = 0.95 is:

z = 1.960

Solving (c): Margin of error

This is calculated as:

E = z * \frac{\sigma}{\sqrt n}

E = 1.960 * \frac{5}{\sqrt {150}}

E = 1.960 * \frac{5}{12.25}

E =  \frac{1.960 *5}{12.25}

E =  \frac{9.80}{12.25}

E =  0.800

Solving (d): The confidence interval

This is calculated as:

CI = (\bar x - E, \bar x + E)

CI = (7.10 - 0.800, 7.10 + 0.800)

CI = (6.3, 7.9)

Solving (d): The conclusion

We are 90% confident that the average number of hours worked by the students is between 6.3 and 7.9

6 0
3 years ago
Need help ASAP please
Sveta_85 [38]

Answer:

bruh ur so dumb

Step-by-step explanation:

google it

5 0
3 years ago
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