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Softa [21]
3 years ago
12

Step 1, when solving a two dimensional, multi-charge problem, is to define the vectors. Please identify the next five steps, in

order.
Calculate the magnitude of R
sum vector components
calculate A and B magnitudes
calculate the direction of R
calculate x,y components
Physics
2 answers:
lora16 [44]3 years ago
5 0

Explanation :

Vectors are the quantities that have both magnitude as well as direction. In order to solve two dimensional multi charge problem, the steps are as follows :

(i) First step is to define vectors.

(ii) Second step is to find the magnitudes of vectors. For example the vector is A =x\hat {i}+y\hat {j}+z\hat{k}. So, |A|=\sqrt{x^2+y^2+z^2}

(iii) Third step is to find x and y components.

(iv) Fourth step is to sum vector components.

(v) Fifth step is find magnitude of resultant vector (R)

(vi) Last step is to find direction of resultant vector.

Hence, this is the correct order.

Masja [62]3 years ago
4 0
Step 2: calculate A and B magnitudes
Step 3: calculate x, y components
Step 4: sum vector components
Step 5: calculate magnitude of R
Step 6: calculate direction of R
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<em> The planes average acceleration in magnitude and direction = 8.846 m/s² moving east</em>

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A small mailbag is released from a helicopter that is descending steadily at 3 m/s.
mario62 [17]

<u>Answer:</u>

a) Speed of mailbag after 3 seconds = 32.4 m/s

b) Package is 44.1 meter below helicopter

c) If the helicopter was rising steadily at 3.00 m/s

       Speed of mailbag after 3 seconds = 26.4 m/s

       Package is 44.1 meter below helicopter

<u>Explanation:</u>

a)  We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

   Initial velocity = 3 m/s, acceleration = 9.8 m/s^2 and time = 3 seconds.

   v = 3+9.8*3 = 32.4 m/s

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b) We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

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    s= 3*3+\frac{1}{2} *0*3^2\\ \\ s=9m

    Distance traveled by helicopter = 9 meter.

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  s= 3*3+\frac{1}{2} *9.8*3^2\\ \\ s= 53.1m

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So package is (53.1-9)meter below helicopter = 44.1 m

c) Initial velocity = -3 m/s, acceleration = 9.8 m/s^2 and time = 3 seconds.

  v = -3+9.8*3 = 26.4 m/s

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    s= -3*3+\frac{1}{2} *0*3^2\\ \\ s=-9m

    Distance traveled by helicopter = 9 meter.

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  s= -3*3+\frac{1}{2} *9.8*3^2\\ \\ s= 35.1m

  Distance traveled by package  = 35.1 meter.

So package is (35.1+9)meter below helicopter = 44.1 m

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