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Alex Ar [27]
3 years ago
15

a bungee jumper of mass 50 kg jumps from a bridge using a 10 m long cord which can be approximated as a spring with spring const

ant 100 n/m. how far is he going to go below the bridge is he going to go before momentarily stopping
Physics
1 answer:
Maslowich3 years ago
3 0

Answer:

25.95 m

Explanation:

m = mass of the bungee jumper = 50 kg

k = spring constant of the cord = 100 N/m

x = stretch of the cord

L = length of the cord = 10 m

h = height dropped by the bungee jumper = L + x = 10 + x

Using conservation of energy

Spring potential energy = gravitational potential energy

(0.5) k x² = mg h

(0.5) (100) x² = (50) (9.8) (10 + x)

x = 15.95 m

d = distance traveled below the bridge

d = L + x

d = 10 + 15.95

d = 25.95 m

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Explanation:

We know that

1 cm = 0.01 m

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f = \frac{(2n - 1)V}{4L}

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Inserting the values

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f = \frac{340}{4(0.025)}

f = 3400 Hz

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