All categories

3 years ago

In the diagram, the wavelength is shown by :

Physics

1 answer:

MAXImum [283]3 years ago

6 0

Answer:

i think the anwer is C

Explanation:

You might be interested in

Water can be found in solid, liquid, and gaseous states. Which two processes would result in water changing to water vapor (or s

slava [35]

Answer:

sublimation and evaporation

Explanation:

evaporation is from liquid to gas and sublimation is solid to liquid, as water vapor is a gas both of these methods could be used

4 0

3 years ago

If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.

White raven [17]

Answer:

400ft. 32ft/s -32ft/s

Explanation:

In reality the gravitational acceleration is 9.81 so the quadratic coefficient of the function should be 9.81/2

Anyway for the sake of assumtion let us takes=160t-16t^2

ds/dt=160-32t=0

t=160/32= 5 seconds.

s=160*160/32-16*(160/32)^2= 400 mts

s=384 mts

160t-16t^2=384

i.e

16t^2-160t+384=0

t^2-10t+24=0

(t-6)(t-4)=0

t=[4,6]

we have to take t=4 because it is all the up i.e <5

velocity =v=ds/dt=160-32t

v=160-32*4=32 ft/sec still going up

for all the way down take t=6 whuch is >5

v=160-6*32=-32 ft/sec (falling down!!!)

6 0

3 years ago

In a mail-sorting facility, a 2.50-kg package slides down an inclined plane that makes an angle of 20.0° with the horizontal. Th

lawyer [7]

Answer:

The coefficient of kinetic friction is 0.382.

Explanation:

Given:

Angle of inclination is, $\theta=20.0$ °

Mass of package is, $m=2.50\ kg$

Initial speed of package is, $u=2.00\ m/s$

Final speed of the package at the bottom is, $v=0\ m/s$

Distance of travel along the incline is, $d=12.0\ m$

Acceleration due to gravity is, $g=9.8\ m/s^2$

Let the coefficient of kinetic friction be $\mu$ .

Now, the frictional force will be acting along the incline but in the direction opposite to the direction of motion.

So, the net acceleration acting on the package will be up the incline and is equal to:

$a=\mu g\cos\theta-g\sin\theta$ ----------------- 1

Now, using equation of motion, we have:

$v^2-u^2=2ad\\\\0-(2.00)^2=2a(12.0)$

Solving for 'a', we get:

$-4.00=24.0a\\\\a=-\frac{4}{24}=-\frac{1}{6}\ m/s^2$

Now, plug in the value of 'a' in equation (1). This gives,

$\mu g\cos\theta-g\sin\theta=\frac{1}{6}$ ( Neglecting negative sign)

Plug in all the given values and solve for $\mu$ . This gives,

$9.8(-sin(20)+\mu cos(20))=\frac{1}{6}\\\\-0.342+\mu\times 0.94=0.017\\\\0.94\mu=0.342+0.017\\\\0.94\mu=0.359\\\\\mu=\frac{0.359}{0.94}=0.382$

Therefore, the coefficient of kinetic friction is 0.382.

5 0

3 years ago

What is weightlessness ?

VMariaS [17]

Answer:

The state of being free from the effects of gravity.

7 0

3 years ago

Distance = 6 km south<br><br> 60 minutes<br><br> What was the average velocity

blsea [12.9K]

v = x/t

v = average velocity, x = displacement, t = elapsed time

Given values:

x = 6km south, t = 60min

Plug in and solve for v:

v = 6/60

v = 0.1km/min south

3 0

3 years ago

Read 2 more answers