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solong [7]
3 years ago
8

Find the zero(s) of function algebraically f(x)=3x+27

Mathematics
1 answer:
Alja [10]3 years ago
3 0
The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace y with 0 and solve for x.

Answer:
x = -9
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What value of x makes the equation true <br> 2 (6x-1) = -38
Anestetic [448]

Answer:

<h3>\boxed{\bold{\boxed{ \sf{x =  - 3}}}}</h3>

Step-by-step explanation:

\sf{2(6x - 1) =  - 38}

Distribute 2 through the parentheses

⇒\sf{12x - 2 =  - 38}

Move constant to right hand side and change it's sign

⇒\sf{12x =  - 38 + 2}

Calculate

⇒\sf{12x =  - 36}

Divide both sides of the equation by 12

⇒\sf{ \frac{12x}{12}  =  \frac{ - 36}{12} }

Calculate

⇒\sf{x =  - 3}

Hope I helped!

Best regards!!

5 0
3 years ago
The system of equations has how many solutions? y=-3/2x+5 and y=-3/2x-3
mixas84 [53]
Here the right side of the 2 equations (which are different)   both equal y
so 0 solutions
8 0
4 years ago
Don’t worry bout the answer on the top but can someone help with two and fast ...???
NemiM [27]
I believe it’s $25.50
5 0
3 years ago
Consider the quadratic equation x2=4x-5. How many solutions does the equation have
Norma-Jean [14]
The quadratic formula is =(-b+-sqrt(b^2-4ac))/2a
as you notice the term under the square root is b^2-4ac if it is postive then the equation clearly will have two real soultions if it is negative then the equation will have two imaginary soultion if it is zero then the the equation will have one soultion
so let us calculate b^2-4ac for our given equation
x^2=4x-5 so let us write it in general form which is ax^2+bx+c=0
subtracting 4x from both sides
x^2-4x=-5
adding 5 to both sides
x^2-4x+5=0
a=1,b=-4,c=5
b^2-4ac=(-4)^2-4(1)(5)=16-20=-4
which means the equation has two imaginary soultions
3 0
4 years ago
Read 2 more answers
If <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7By%7D" id="TexFormula1" title="\frac{x}{y}" alt="\frac{x}{y}" align="absmid
Delicious77 [7]
This is your answer say me if I am wrong

4 0
3 years ago
Read 2 more answers
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