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miss Akunina [59]
3 years ago
5

Taylor, Moore, and Jenkins are candidates for public office. It is estimated that Moore and Jenkins have about the same probabil

ity of winning, and Taylor is believed to be twice as likely to win as either of the others. Find the probability of each candidate winning the election.
Mathematics
1 answer:
katrin [286]3 years ago
3 0

Answer:

Taylor = 50%

Moore = 25%

Jenkins = 25%

Step-by-step explanation:

Assuming there are no other candidates and that someone has to win the election, the probabilities of Taylor, Moore, and Jenkins winning the election must add up to 1 or 100%.

T+M+J = 1\\

Since Moore and Jenkins have about the same probability of winning, and Taylor is believed to be twice as likely to win as either of the others:

M=J\\T=2J\\J+J+2J=1\\J=0.25\\M=J=0.25\\T=2*0.25=0.5

Taylor has a probability of 50% of winning the election.

Moore has a probability of 25% of winning the election.

Jenkins has a probability of 25% of winning the election.

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Which equation could be used to find the length of the hypotenuse?
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Answer:

2^2 +5^2 = c^2

Step-by-step explanation:

We can use the Pythagorean theorem to solve for c

a^2 + b^2 =c^2  where a and b are the legs and c is the hypotenuse

2^2 +5^2 = c^2

4+25 = c^2

29 =c^2


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3 years ago
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For the point P(2,-14) and Q(9,-9) find the distance d(P,Q) and the coordinates of the midpoint M of the segment PQ
marin [14]

Answer:

Step-by-step explanation:

Distance : \sqrt{(x2-x1)^2 + (y2 - y1)^2} = \sqrt{(9-2)^2 + (-9+14)^2}= \sqrt{49 + 25} = \sqrt{74}

Midpoint :

x (m) = (2+9)/2 = 11/2

y (m) = (-14-9)/2 = -23/2

M (11/2, -23/2)

5 0
3 years ago
The quantity of soda consumed per week at a soda fountain is 34 liters, with a standard deviation of 5.8 liters. If any 80 weeks
Mademuasel [1]
D. 0.648 HAPPY TO HELP!
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Suppose it snowed 5 inches in 2 days. Then 5/2 describes the average daily snowfall. Write the improper fraction as a mixed numb
cricket20 [7]

Answer:

5/2 = 2 1/2

Step-by-step explanation:

There are 2 parts in one half, meaning 2 halves equals 1.

If you have 5 halves, you of course would get an improper fraction.

To find the answer, dive the numerator by the denominator. 5 ÷ 2 gives you 2.5, or 2 1/2.

Think about it this way: How many times does will 2 go in to 5 evenly? Twice. 2 times 2 is 4, leaving you with one left over. Whatever the remainder is, is the numerator for the improper fraction, and the denominator stays the same.

6 0
3 years ago
Let x = a bi and y = c di and z = f gi which statements are true? check all of the boxes that apply. x y = y x (x × y) × z = x ×
Alex73 [517]

A complex number is a part of a number system that includes a real unit and an imaginary unit. All the statements are true except C and E.

<h3>What is a Complex Number?</h3>

A complex number is a part of a number system that includes the real numbers as well as a particular element labelled i, sometimes known as the imaginary unit, and which obeys the equation i² = 1.

As it is given that x=(a+bi), y=(c+di), and z=(f+gi), therefore, we need to plug in the values to check which all are true.

A.) x+y=y+x

x+y=y+x\\a+bi+c+di=c+di+a+bi

As the two sides of the equation are equal, the equation is true.

B.) (x × y) × z = x × (y × z)

(x \times y) \times  z = x \times  (y \times  z)\\\\\ [ (a+bi)  \times (c+di) ]\times (f+gi) = (a+bi)  \times [(c+di) \times (f+gi)]\\\\(ac+adi+bci-bd) \times (f+gi)=  (a+bi)  \times (cf+cgi+fdi-dg)

(ac+adi+bci-bd) \times (f+gi)=  (a+bi)  \times (cf+cgi+fdi-dg)\\\\\\acf+adfi+bcfi-bdf+acgi-adg-bcg-bdgi = acf+acgi+afdi-adg + bcfi-bcg-bfd-bdgi

As the two sides of the equation are equal, the equation is true.

C.) x−y=y−x

x-y=y-x\\\\(a+bi)-(c+di)=(c+di)-(a+bi)\\\\a+bi-c-di=c+di-a-bi

As the two sides of the equation are not equal, the equation is not true.

D.) (x+y)+z=x+(y+z)

(x+y)+z=x+(y+z)\\\\(a+bi+c+di)+f+gi = a+bi+(c+di+f+gi)\\\\a+bi+c+di+f+gi = a+bi+c+di+f+gi

As the two sides of the equation are equal, the equation is true.

E.) (x−y)−z=x−(y−z)

(x-y)-z=x-(y-z)\\\\(a+bi-c-di)-f-gi = a+bi-(c+di-f-gi)\\\\a+bi-c-di-f-gi =a+bi-c-di+f+gi)

As the two sides of the equation are not equal, the equation is not true.

Hence, all the statements are true except C and E.

Learn more about Complex Number:

brainly.com/question/12464608

6 0
2 years ago
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